Venkatesh kadali   9 years AGO

multiples of 3 are upto 20 are :3
6
9
12
15
18
total number of favoirable choices are :6
total number of choices are: 20
so probability is=6/20
=3/10
so answer is 2

Like? Yes (7) | No (1)  

sudesna mukherjee   9 years AGO

multiple of =3,6,9,12,15,18.
so 6/20
=3/10

Like? Yes (4) | No (1)  

MRITUNJAY   9 years AGO

n(e)=3 6 9 12 15 18=6
n(s)=20
p=6/20
=3/10

Like? Yes (3) | No (1)  

Ankita Sharma   9 years AGO

Total no. of tickets=20
Tickets having numbers multiple of 3=6
Reqd Probability=6/20=3/10

Like? Yes (2) | No   

Shashank Gupta   9 years AGO

Total=20
Multiple of 3 b/w 1 to 20 = 6 {3,6,9,12,15,18}
probablity=6/20 = 3/10(ans)

Like? Yes (2) | No   

priyanka burnwal   9 years AGO

no. divisible by 3 is 3,6,9,12,15,18=6
probability =6/20=3/10..

Like? Yes (2) | No   

vanitha thummala   9 years AGO

multiples of 3 are 6....
so p=6/20
=3/10

Like? Yes (2) | No   

Shyamnks    9 years AGO

Total number of possible outcomes while rolling a die = 20
possible outcomes are multiples of 3 = 3,6,9,12,15,18=6
So the probability of getting a multiple of 3
= No. of desirable outcomes (multiple of 3)/No of possible outcomes
= 6/20
=3/10

Like? Yes (2) | No   

sanchit soni   9 years AGO

multiple of 3 = 3 6 9 12 15 18 = 6 = fav. outcomes
total poss. outcomes = 20
prob. = 6/20 = 3/10 ans.

Like? Yes (2) | No   

SAGNIK DATTA   9 years AGO

there are 6 multiples of 3 less than 20
so 6/20=3/10

Like? Yes (1) | No   

suresh sahu   9 years AGO

total possible no-3,6,9,12,15,18
and total out come 20
so p=6/20=3/10

Like? Yes (2) | No (1)  

PRAGATHI G   9 years AGO

multiples of 3 are 3,6,9,12,15,18.. so out of 20 tickets. . any of des 6 may come. hence prob is 6/20. which is 3/10

Like? Yes (1) | No   

vikas kulshrestha   9 years AGO

p(E)=6
P(S)=20
P=P(E)/P(S)
=6/20
3/10

Like? Yes (2) | No (1)  

sudhir kumar maurya   9 years AGO

multiples of 3 =(3,6,9,12,15,18) = 6
total sample space=20
p=6/20=3/10

Like? Yes (1) | No   

Sonu kumar   9 years AGO

total case=20
no.of events=3,6,9,12,15,18=6

probability= 6/20=3/10.

Like? Yes (1) | No   

Akash Kumar   9 years AGO

total numbers=20
and favourable numbers are 3,6,9,12,15,18
so favourable case=6
therefore probability is=6/20=3/10.

Like? Yes (1) | No   

Lakhi kant Roy   9 years AGO

from 1 to 20 there are 6 multiples of 3 i.e is--3,6,9,12,15,18,
and sample space=20
so,Required Probability=6/20
=3/10

Like? Yes (1) | No   

Shubham Raj   9 years AGO

Here, S = {1, 2, 3, 4, ...., 19, 20}.

Let E = event of getting a multiple of 3 or 5 = {3, 6 , 9, 12, 15, 18 }.
n(E) = 6
n(S) 20
P(E) =6/20
=3/10

Like? Yes (1) | No   

sudiptaa   9 years AGO

multiples of 3= 3,6,9,12,15,18
n=6
p= 6/20 = 3/10

Like? Yes (1) | No   

Testing Account   9 years AGO

number which is multiple of 3 are.....3,6,9,12,15,18
total number which is multiple of 3 is 6
so probability of getting multiple of 3 is......3/10

Like? Yes (1) | No   

ramya   9 years AGO

Here, S = { 1,2,....20}.

Let E = event of getting a multiple of 3 = {3, 6 , 9, 12, 15, 18,}.
P(E)=n(E)/n(S)=6/20
=3/10

Like? Yes (1) | No   

Appasaheb Sole   9 years AGO

possibilites:-3,6,9,12,15,18
total fav cases=6
prob:-fav.cases/total cases
p=6/20=3/10

Like? Yes (1) | No   

sravani   9 years AGO

there are 6 multiples of 3 in 1 to 20...so
6/20 is the probability.=3/10...

Like? Yes (1) | No   

Neelaksh Mishra   9 years AGO

multiples of 3 are 3,6,9,12,15,18 therefore number of multipls 6
then total outcomes are 20
therefore 6/20=3/10

Like? Yes (1) | No   

Kunal nemu   9 years AGO

Here S ={1,2,3,...........,19,20}
Let E = event of getting a multiple of 3 ={3,6,9,12,15,18}
So P(E) = n(E) / n(S) = 6 / 20 = 3 / 10

Like? Yes (1) | No   

NAIKWADE SURAJ LAXMAN   9 years AGO

among 1 to 20 numbers , 6 numbers are multiples of 3, 6/20=3/10

Like? Yes (1) | No   

RAVAL   9 years AGO

multiple of 3 in 1 to 20 are 3,6,9,12,15,18
so, total no is 6 out of 20
ans.=6/20 = 3/10

Like? Yes (1) | No   

Indranil Bhattacharya   9 years AGO

Here, S = {1, 2, 3, 4, ...., 19, 20}.

Let E = event of getting a multiple of 3 or 5 = {3, 6 , 9, 12, 15, 18}.

P(E) = n(E) = 6 .
n(S) = 20

Answer: 3/10

Like? Yes (1) | No   

adi   9 years AGO

Total possible outcomes=6
Total outcomes=20
Probabilities=6/20=3/10

Like? Yes (1) | No   

ABHIJIT GURUDATTA PATIL   9 years AGO

no.s wich are multiple of 3=3,6,9,12,15,18
total multiples no.s=6
total no.s=20
prob.=6/20=3/10

Like? Yes (1) | No   

Deepanshu Chaturvedi   9 years AGO

3,6,9,12,15,18----------------6 outtcomes
20--------------------------------total otcomes
probability = 6/20 = 3/10

Like? Yes (1) | No   

Praveenkumar J   9 years AGO

3,6,9,12,15,18...multiples of 3=6
Total numbers=20
Probability=6/20=3/10

Like? Yes (1) | No   

harman kaur   9 years AGO

because number of multiples of 3 are 6 and probability=6/20=3/10

Like? Yes (1) | No   

ayushi   9 years AGO

multiples of 3 are : 3,6,9,12,15,18
hence probability=6/20=3/10

Like? Yes (1) | No   

pranay kumar   9 years AGO

its answer is 3/10 because there are 6 numbers which are multiple of 3 between the numbers from 1 to 20. multiples are 3,6,9,12,15 and 18 .so total 6 of them..so,

probability = possible outcome / total given outcome
= 6/20 = 3/ 10 (answer )..so option 2 is correct..

Like? Yes (1) | No   

lakshmi priya   9 years AGO

6 numbers which r multiples of 3 so 6/20

Like? Yes (1) | No   

praveen   9 years AGO

There are 20 papers.....multiples of 3 upto 20 are 3,6,9,12,15,18..
Therefoe probability is 6/20 i.e, 3/10

Like? Yes (1) | No   

pratibha   9 years AGO

3,6,9,12,15,18 are the multiple of 3
so, total no. of digits is 20
6/20=3/10

Like? Yes (1) | No   

mounika   9 years AGO

probability of an event=probability of occuring/total number of events

Like? Yes (1) | No   

Moumita Choudhury   9 years AGO

Total numbers multiple of 3 = 6
Total numbers 20
Probability = 6/20 = 3/10

Like? Yes (1) | No   

asim   9 years AGO

between 1 to 20 there is 6 numbers which is multiple of 3 so probable outcome by total outcome gives 3/10.

Like? Yes (1) | No   

lavanya lahari   9 years AGO

multiples of 3 between 1 and 20 are 3,6,9,12,15,18....so probablity=6/20=3/10

Like? Yes (1) | No   

Arvind kumar   9 years AGO

nos. divisible by 3 between 1 to 20 are 3,6,9,12,15 and 18 i.e. there are six nos.
so,probability of taking a ticket is 6c1/20c1
i.e. 6/20 i.e 3/10

Like? Yes (1) | No   

Mahalakshmi   9 years AGO

possible ways to get multiples of 3 = 6 (3,6,9,12,15 and 18)
Total possibility =20
So 6/20 = 3/10

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Surya.v   9 years AGO

multiples of 3 from 1 to 20: 3,6,9,12,15,18.
n(a) = 6
n(s) = 20
p(a) = n(a)/n(s)
= 6/20
= 3/10.

Like? Yes (1) | No   

gvsmaneesha   9 years AGO

no.ways to select a ticket from 20 is 20 ways and there are 6 cards..(3,6,9,12,15,18) multiple of 3.. so 6/20 is the answer on simpilfying it we get.. 3/5

Like? Yes (1) | No   

sukriti singh   9 years AGO

chances of getting multiple of 3 is 3,6,9,12,15,18
nd total cards are. 20 so,
6/20=3/10

Like? Yes (1) | No   

Sandeep Kumar   9 years AGO

No of probability which is multiple of 3 = 6
No of total number = 20

P(n) = 6/20 = 3/10

Like? Yes (1) | No   

adarsh   9 years AGO

6 tickets are the multiple of 3 probability =6/20=3/10

Like? Yes (1) | No   

Sasidhar   9 years AGO

There are 6 multiples of 3 from 1-20
And can be selected in 6 ways
The total no of selections is 20
ie n(p)=n(e)/n(s)
=6/20
=3/10

Like? Yes (1) | No   

riya srivastava   9 years AGO

no. of outcomes =6
total no. of outcomes=20
probability=6/20=3/10

Like? Yes (1) | No   

J E Tejeswar Gowd   9 years AGO

multiples of 3 with in first 20 natural numbers is 6 i.e.,(3,6,9,12,15,18)
prob=6/20
=3/10

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Deepak kumar singh   9 years AGO

only 6 no's 3,6,9,12,15,18 can be taken from the given series.
so the prob will be 6/20=3/10

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nithin gb   9 years AGO

multiples of 3=3,6,9,12,15,18=6
20 tickets are their
6/20=3/10

Like? Yes (1) | No   

Ajay Kumar Gupta   9 years AGO

probability of getting multiple of 3 i.e {3,6,9,12,15,18} are=6/20=3/10.

Like? Yes (1) | No   

atul vishwakarma   9 years AGO

becoz no of favourable outcome=6
total no of outcome=20

Like? Yes (1) | No   

saurabh kumar   9 years AGO

there are 6 numbers between 1 and 20 which is multiple of 3.so probability=>6c1/20c1,6/20=3/10.

Like? Yes (1) | No   

Amit chaturvedi   9 years AGO

favourable chance= 3,6,9,12,15,18

6/20=3/10

Like? Yes (1) | No   

SHAHARBAN O   9 years AGO

p(event)=n(event)/n(total)
p(event)=n(number of multiples of 3 less than 20)/20
p(event)=6/20 ie, 3/10

Like? Yes (1) | No   

Akhil   9 years AGO

Because we have 6 possible outcomes nd 20 total no of outcomes so 6/20 =3/10

Like? Yes (1) | No   

suresh   9 years AGO

out 20 cards 6 cards are divisible by 3. So the probability is 6/20 which is 3/10

Like? Yes (1) | No   

pragya khanna   9 years AGO

multiples of 3 b/w 1-20 are 6 3,6,9,12,15,18 hence 6/20 = 3/10

Like? Yes (1) | No   

sunil p rao   9 years AGO

multiples of 3 are 3,6,9,12,15,18. total numbers available are 20. so 6/20 = 3/10.

Like? Yes (1) | No   

akshay   9 years AGO

The multiples of 3 within 20 are 3,6,9,12,15,18. That's a total of 6. The probability is 6/20 which is equal to 3/10.

Like? Yes (1) | No