The ratio between the rates of walking of A and B is 2:3 and therefore A takes 10 minute more than t

ABHINAV PUSHPAM   9 years AGO

Ratio of speed = 2:3
Ratio of time = 3:2
A takes 10 min more
3x-2x = 10 min
A time=30 min
A covers the distance in 30 min , if its speed is x
So, He will cover the same distance in 15 min, if its speed
doubles (i.e 2x)

option 1)

Like? Yes (26) | No (4)  

MADHUBABU   9 years AGO

ratio of times of A&B =1/2 : 1/3
If B takes x min, then A takes (x+10) min
therfore (x+10) :x=1/2 : 1/3
=> (x+10)/x =3/2
=> 2x+20= 3x
=> x= 20 min
therfore time taken by A =20+10=30 min
If A had walked at double speed
required time = 30/2 = 15 min.

Like? Yes (14) | No   

sudiptaa   9 years AGO

Ratio of times = 1/2 :1/3
when speed of A is doubled = 4
time taken by A = 1/4*60 = 15 mintutes

Like? Yes (11) | No   

praveendas   9 years AGO

ratio of time taken by them is 3:2 for a certain distance.
given time diff is 10 so times are30:20,
if a doubled his speed then time taken is reduced to half which is 15 min.
option 1

Like? Yes (5) | No   

chinu singla   9 years AGO

As we know speed=1/time;
let time taken by B= x
thus,time taken by A= x+10;
therefore x+10/x=3/2
after solving it we get x=20
thus time taken by A= 20+10=30
AND IF A doubles its speed then its time gets halved
so time taken by A after doubling its speed=30/2=15

Like? Yes (5) | No   

Aman   9 years AGO

A/B=2/3
i.e
A=2
B=3
so
according to equation of speed = distance / time
we got that
let x be the time taken by B
so X+ 10 is the time taken by A
so
2=distance/x+10
and
3= distance / x
now
equating distances
2(x+10)=3x
so
x=20
so
time taken by A= 30
now speed is inversly proportional to time so
if speed doubles time reduces by half
so
time taken by A= 15 Minutes

Like? Yes (5) | No   

ramakrishnateja   9 years AGO

given the rates ratio is 2:3 which means sa:sb=2:3 ta=tb+10. here d is same so 2t1=3t2. 2(t2+10)=3t2 t2=20. hence t1=30.if sa becomes 2sa then t=d/2sa . here d=2t1=2*30=60. sa=2 hence t=60/4=15min.

Like? Yes (4) | No   

avanthika   9 years AGO

Time will be halved 30/2=15min

Like? Yes (6) | No (2)  

SAGNIK DATTA   9 years AGO

(d/2x) - (d/3x) =10 so d= 60x now d/4x = 15 min

Like? Yes (4) | No (1)  

kriti kankariya   9 years AGO

let the speeds be 2x and 3x of A & B rsp
then,
d/2x = d/3x +10 (given A takes 10 min more than B)
solving,d=60x
then if A's speed will be doubled then time taken will be
d/4x
= 60x / 4x
=15 min

Like? Yes (3) | No   

vinusha   9 years AGO

Speed is inversely proportional to time
So when speed doubles, time will be halved
30/2=15min

Like? Yes (3) | No   

Nikhil chavan   9 years AGO

x/y=2/3...3x=2y...D/x=10+D/y...gives D=30x..so we require D/(2x)=15

Like? Yes (3) | No (1)  

Moutam Vishnu Murthy   9 years AGO

Ratio of speed=2:3
Ratio of time=3:2
let A takes 3x hrs,B takes 2x hrs
then 3x-2x=10/60 hr
x=1/6 hr
Time taken by A to reach the destination is 3x= 3*1/6= 30mins
If A had walked at double the speed he will reach in 15mins.

Like? Yes (2) | No   

Testing Account   9 years AGO

4

Like? Yes (2) | No   

rahul shaw   9 years AGO

diff between their ratio is 1=10 min
2:3=is the walking speed ratio
time ratio is 30:20
since their diff is 10
so
.if A doubles its speed then he would reach in 15mins

Like? Yes (2) | No   

TONI PRIYA   9 years AGO

let B takes time t,then A will take (t+10) time
so (x/(t+10))/(x/(t))=2/3
after solving this we will get t=20.
t+10=30.
That's why A takes 30 min
In that way,if A had walked at double speed,he would have covered the distance in 15 min.

Like? Yes (1) | No   

sravani   9 years AGO

speed is inversely proportional to time so,
time will be x/2 and x/3
x/2-x/3=10min
x=60 mins
so,A takes 30 mins at present
If speed is doubled then time will be 15 mins.

Like? Yes (1) | No   

RENU KUMARI   9 years AGO

s1=2*(2/3s2)
d/t1=2*(2d/3t2)
t1=t2+10
so, t2=5
and t1=15

Like? Yes (1) | No   

Divyashree   9 years AGO

ratios of speeds of A and B is 2:3
ratios of time taken by A and B is 3:2
A/B=3/2
2A=3B
given A=B+10
A=(2A/3)+10
A=30
B=20
if A has walked at double the speed,he would have covered the distance in 15 minutes
therefore, ans is 1)15 minutes

Like? Yes (1) | No   

S.Hemanth kumar   9 years AGO

the ratio of a @b is =1/2:1/3
suppose B takes x min then A takes x+10 min
so x+10/x =3/2
x=20
A=20+10=30
A takes double speed so
t=30/2=15 minutes

Like? Yes (1) | No   

shiuli noor alam   9 years AGO

A will cover the same distance with double speed in 15 minutes.

Like? Yes (1) | No   

Tanya Sachdev   9 years AGO

A with previous speed covers the distance in 30 min if the speed is doubled time reduced to half 15 min

Like? Yes (1) | No   

Surendra Naraga   9 years AGO

Ratio of speed = 2:3
Ratio of time = 3:2
A takes 10 min more
3x-2x = 10 min
A time=30 min
A covers the distance in 30 min , if its speed is x
-> He will cover the same distance in 15 min, if its speed
doubles (i.e 2x)

Like? Yes (1) | No   

Shubham Raj   9 years AGO

right answer is 15 min
option-1

Like? Yes (1) | No   

Gugulothu vijaykumar   9 years AGO

Ratio of speed = 2:3
Ratio of time = 3:2
A takes 10 min more
3x-2x = 10 min
A time=30 min
A covers the distance in 30 min , if its speed is x
-> He will cover the same distance in 15 min, if its speed
doubles (i.e 2x)

Like? Yes (1) | No   

H. Sreekanth   9 years AGO

Ratio of speed = 2:3
Ratio of time = 3:2
A takes 10 min more
3x-2x = 10 min
A time=30 min;
A covers the distance in 30 min , if its speed is x
- He will cover the same distance in 15 min, if its speed
doubles (i.e 2x)

Like? Yes (1) | No   

venkatesh   9 years AGO

a:b=2:3
a=b+10
b=20
a=30
but double the speed
so a=30/2=15
s0 15

Like? Yes (2) | No (1)  

pravallika   9 years AGO

case i:speed is inversely proportional to time
so,2/3=t/(t+10)
implies 3t=2t+20;t=20;
it means a covers it in 30 min.
case ii)if speed of a doubles ,then 4/3=20/t
implies t=15 min.
therefore,if speed of A doubles,then he covers the distance in 15 min.

Like? Yes (1) | No   

aditi kumari   9 years AGO

let a speed is 2 m/sec and B speed is 3 m/sec and time taken by A to reach destination is X sec.
THEn according to question time taken by B =X-10 sec.
2X=3(x-10)
x=30 sec.
total distance cover =30* 2=60m.
now if A double his speed then speed =4m/sec.and now time taken by a =60/4=15 sec.

Like? Yes (1) | No   

Pesari Udayasree   9 years AGO

ratio of speed and time as 2:3 and 3:2
let a takes 3x hrs and b takes 2x hrs then 3x-2x=10/60hr
x=1/6 hr
then 3x=3(1/6)=30 min.which is the time taken by a to reach the destination
if a had walked at double the speed he will reach in 15min.
so answer is 15min.

Like? Yes (1) | No   

SUMIT PAREEK   9 years AGO

Ratio of times taken by A & B=1/2 : 1/3
let B takes x min , then A takes (x+10) min
(x+10 : x)=1/2 : 1/3
so, (x+10)/x=3:2
x=20
time taken by A=20+10=30 min
If A had walked double speed , then
required time = 30/2= 15 min

Like? Yes (1) | No   

Abhijit Das   9 years AGO

Ta =Tb + 10
D/2x = D/3x + 10

therefore , D= 60x
speed doubled 2* 2x= 4x
60x/4x = 15
ans= 15 mins

Like? Yes (1) | No   

NITESH KUMAR SINGH   9 years AGO

let thec speed be 100
so speed of a=40 and speed of b=60
time taken by a=x/40
and b=x/60
so x=1200
and speed=80
sotime=1200/80=15min

Like? Yes (1) | No   

Anup Sahay   9 years AGO

let speed and time of A be s1 and t1 and let speed and time of B be s2 and t2
so speed to time ratio : s1/s2=t2/t1
so, 2/3=t2/t2+10
t2=20 mins
so t1=30 mins
now d=s1*t1=2*30=60
so if
60=4*s1'
s1'=15 mins answer

Like? Yes (1) | No   

chetan   9 years AGO

actual time=30 mins
if doubles the speed 15 mins

Like? Yes (1) | No   

ramya   9 years AGO

Speed = Distance / time.
Based on the ratios the option is 1)

Like? Yes (1) | No   

Arvind kumar   9 years AGO

If ratio is 2:3 and A takes 10 minute more than A takes 30 minute and B takes 20 minute.
therefore,if A walked with double speed , he would cover the distance in 15 minute.

Like? Yes (2) | No (1)  

GURRAM MAHENDRA   9 years AGO

Ratio of speed = 2:3
Ratio of time = 3:2
A takes 10 min more 3x-2x = 10 min
A time=30 min
-->A covers the distance in 30 min , if its speed is x
-> He will cover the same distance in 15 min, if its speed
doubles (i.e 2x)

Like? Yes (1) | No   

vaibhavi lodhiya   9 years AGO

23=x/x+10;so t=60/4
T=15min

Like? Yes (1) | No   

gaurav singh   9 years AGO

Ratio of speed = 2:3
Ratio of time = 3:2
A takes 10 min more
3x -2x = 10 min
A time=30 min
A covers the distance in 30 min , if its speed is x
He will cover the same distance in 15 min, if its speed
doubles

Like? Yes (1) | No   

Rohit Agrawal   9 years AGO

d/2x=d/3x+10
=>d/x=60
=>d/4x=15 ... answer

Like? Yes (1) | No   

patki shrikant   9 years AGO

speed double time half.
so now time taken by a =30
again speed double time half=15

Like? Yes (1) | No   

Deepanshu Chaturvedi   9 years AGO

let y be time taken.from question x/30=y and x/20=y+1/6 solving we get y=1/3 hours=20 minutes.'A' takes 10 minute more means 30 minutes.doubling speed means time become half i.e.15 minutes.

Like? Yes (1) | No   

sandeep prasad   9 years AGO

the ratio is 20 min and 30 min so if a take 30 min by x speed then he take 15 min by 2x speed

Like? Yes (2) | No (1)  

kandi sindhuja reddy   9 years AGO

Speeds a:b is 2:3,let time taken by b is x,then speed is inversely propirtional to time,i.e., 2:3=x:x+10,x=20,then time taken by a is 30mins,if speed of a is doubled then time will be half then a takes 15mins.

Like? Yes (1) | No   

Sayandeep Jana   9 years AGO

A takes=x+10 min
B takes=x min
using ratio we get x=30

Like? Yes (1) | No   

nirmal das   9 years AGO

let speed of A and B is 2x and 3x and distance is y...
so (y/2x)-(y/3x0=10 fromthis we get y=60x
now 60x/4x=15 so A takes 15 minutes

Like? Yes (1) | No   

Ashish Kumar Singh   9 years AGO

let's assume that B take x min to cover then A takes x+10 min to cover same distance.
3x=(x+10)2
x=20 min
A takes 30 min.
If speed of A is double.
then he takes 15 min.

Like? Yes (1) | No   

Belal Ahmed   9 years AGO

let the distance be x
then x/2 - x/3 = 10
x=60
if a's speed is double the time is 60/4=15mins

Like? Yes (1) | No   

utkarsh mittal   9 years AGO

let distance be x and A speed be 2y and B speed be 3y
x/2y-x/3y=10
x = 60y
then time of A is 15 min

Like? Yes (1) | No   

YASWANTH REDDY   9 years AGO

let speeds of A and B be 2V and 3V respectively.
As time and velocity are inversely proportional, and t be the time taken by B to reach the destination, then
2/3 = t/(t+1/6) and we get t = B's time = 20 min, and A's time = 30 min. If he travels with double speed, then time gets halved and therefore time taken by A to reach the destination with double the speed = 15 min

Like? Yes (1) | No   

Divya   9 years AGO

First take A:B=2:3 that means speeds in ratio of 2:3 and given time by A is t+10 and B is t and then by solving with equal distance then we get t=20.After that as speed is doubled we get 15 minutes as answer

Like? Yes (1) | No   

Siva   9 years AGO

Let the speeds of A and B are 2x and 3x respectively. The time taken by B be t, then the time taken by A is t+10.
2x(t+10)=3xt,
2xt+20x=3xt,
xt=20x,
t=20.
The time taken by B is 20, so time taken by A is 30.
(S1:S2)=(T2:T1),
(S1:2 S1)=(T2:30),
T2=(30÷2)=15.
If the A walk at double speed he will reach in 15 minutes.

Like? Yes (1) | No   

Subhasri Pal   9 years AGO

Let the speeds of A and B be 2x and 3x respectively.
and time taken by A and B be y+10 and y respectively.
therefore equating,
2x(y+10)=3xy
or,2xy+20x=3xy
or,xy=20x
0r,y=20
so, y+10=30.
so time taken by A is 30 mins.
therefore, if the speed of A is doubled time taken would be halved.
hence, 15 mins.

Like? Yes (1) | No   

akanksha    9 years AGO

Time taken by A is =time taken by B-10
Distance/2x=distance/3x-10
Distance=60x
If speed of A double then time =
60x/2×2x
=15 min

Like? Yes (1) | No   

PAWAN KUMAR   9 years AGO

1/4 *60 MIN = 15 MIN.

Like? Yes (1) | No   

Sinthiya Jana   9 years AGO

let distance=n,
speed of A and B is 2x and 3x respectively.
then,
n/2x-n/3x=10
=>n/x=60
now time taken by A is n/2x=60/2=30
and time taken by B is n/3x=60/3=20
total time=50
now speed of A become 4x.
so time taken by A is 60/4=15

Like? Yes (1) | No   

pradyumn   9 years AGO

let x is distance
so x/2 = x/3+10
-> x= 60
now new speed = 4
-> time = 15

Like? Yes (1) | No   

sireesha.yammanuru   9 years AGO

Given ratio of the speeds of A,B is
A : B = 2X:3X---(1)
let At = time taken to reach destination by A & smiliarly Bt by B
given At = Bt+10 min --(2)
we know that speed×time = constant for same distance
A×At = B×Bt --(3)
solving above 3 equations we get
At = 30 min
for a speed of 2X it takes 30 min
then for a double speed i.e 4X speed it takes 15 min only.. bcse s×t = dstane (constant)

Like? Yes (1) | No   

Kiran Notwani    9 years AGO

Rate is 2/3
Suppose B takes X minutes so A takes X+10 minutes

Hence 2/3=X/X+10

X gives 20 hence B Takes 20 minutes and A takes 30

At double speend A will take only 15

Like? Yes (1) | No   

diksha   9 years AGO

speed is inversly propotional to time.
so if speed is doubled, time will be half .
At first speed of A, time can be calculated by equalling the distance travelled by both A & B

Like? Yes (1) | No   

jayaram   9 years AGO

Ratio of times taken by A and B=1/2:1/3
suppose Btakes x min.Tehn A takes (x+10)min
(x+10):x=1/2:1/3
(x+10)/x=3/2
2x+20=3x
x=20;
Time taken by A=20+10=30;
if A walked at double speed
=30/2=15min

Like? Yes (1) | No   

ANKUR BAJWA   9 years AGO

Speed of A=2x
Speed of B=3x
time taken by B=t mins
time taken by A=(10+t) mins
from formula s=v*t
distance covered by A=Distance covered by B
2x * (10+t)=3x * t
20 + 2t=3t
t=20 mins
So time taken by A=20+10=30 mins
And Time taken by B=10 mins
Now speed of A is double so speed of A=2*2x=4x
But distance is same
So time taken by A to covered this distance by double speed=t1
So
again from s=v*t
distance covered by A with 2x speed=distance covered by B with 4x speed
2x * 30=4x*t1
60=4t1
t1=15 mins (answer)

Like? Yes (1) | No   

swathi   9 years AGO

Ratio of speed = 2:3
Ratio of time = 3:2
A takes 10 min more
3x-2x = 10 min
A time=30 min
ÆA covers the distance in 30 min , if its speed is x
-> He will cover the same distance in 15 min, if its speed

Like? Yes (1) | No   

dhriti gupta   9 years AGO

d/2x=d/3x+10 solving and equating using this equation

Like? Yes (1) | No   

Arijit Bera   9 years AGO

S(A)-2a*(b+10) ,S(B)-3ab [b=time]
time taken by A=2a(b+10)/4a
solving previous eqation get b=20
so A(t)-15

Like? Yes (1) | No   

pravin singh   9 years AGO

Ratio of speed = 2:3
Ratio of time = 3:2
A takes 10 min more
3x-2x = 10 min
A time=30 min
A covers the distance in 30 min , if its speed is x
He will cover the same distance in 15 min, if its speed
doubles (i.e 2x)

Like? Yes (1) | No   

Aritra Chakraborty   9 years AGO

A speed = 2k
B speed = 3k
total time taken by B to cover the distance = t
i.e., total distance = 3kt
time taken by A = t+10
i.e., total distance = 2k(t+10)

3kt = 2k(t+10) => t = 20
thus total distance = 60k

double A speed = 4k
time req = 60k/4k = 15 min

Like? Yes (1) | No   

premlata   9 years AGO

ratio of time is reciprocal to speed.

Like? Yes (1) | No   

kiran   9 years AGO

1/2:1/3=x:10
x=15min

Like? Yes (1) | No   

Amit chaturvedi   9 years AGO

Ratio of speed = 2:3
Ratio of time = 3:2
A takes 10 min more
3x-2x = 10 min
A’s time=30 min
A covers the distance in 30 min ,if its speed is x
He will cover the same distance in 15 min,
if its speed doubles (i.e 2x)

Like? Yes (2) | No (1)  

siddhi datri   9 years AGO

Let the time taken by A be t.
then, B will take t-10
therefore,2/3=t-10/t
=>t=30 mins
now if speed is doubled den time will be halved because distance is same
Then New time will be 30/2=15 mins.

Like? Yes (1) | No