A four digit number having all digit successive when substracted by the number formed by using all the digits in reverse pattern (ie reverse of xyz is zyx) gives a four digit number. The sum of all digits of that number is 18. What will be the product of thousand and units digit of that number
Let number is 1000x + 100y + 10z + p (i)
its reverse number will be 1000p + 100z + 10y + x (ii)
(ii) - (i) = 999p + 90z - 90y - 999x
999(p-x) + 90(z-y)
999*3 + 90*1 = 2997+90 = 3087
21
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