If 18 pumps can raise 2170 tonnes of water in 10 days, working 7 hours a day, in how many days will

M4maths Previous Puzzles

10 Nov 2015 Time and work

If 18 pumps can raise 2170 tonnes of water in 10 days, working 7 hours a day, in how many days will 16 pumps raise 1736 tonnes, working 9 hours a day?

OPtion

1) 4 days
2) 5 days
3) 6 days
4) 7 days
5) 8 days
6) 9 days
7) 10 days
8) 12 days
9) 14 days
10)None of these

Solution

Less pumps, more days (Indirect)
Less water, less day (Direct)
More working hours, less day (Indirect)
Pumps 16:18
Water 2170:1736
Working hours 9:7

10:x
Solve x = 18*1736*7*10/16*2170*9 = 7 days
Option 4)

Correct Option: 4 Best Solution (28)

MRITUNJAY   9 years AGO

18*10*7/2170=d*16*9/1736

d=7
option 4

Like? Yes (6) | No (2)  

Nandkishor jaiswal   9 years AGO

from formula
m1*d1*h1/w1=m2*d2*h2/w2
18*10*7/2170=16*d2*9/1736
so d2=7 days

Like? Yes (4) | No   

RAHUL KUMAR   9 years AGO

18 pumps raise 2170 tonnes in 10
days (7 hours)
18 pumps raise 2170 tonnes in
70 hours
1 hour 18 pumps can raise :
2170/70 = 31 tonnes.
1 hour 1 pump can raise
31/18 tonnes
======
=> 1 hour 16 pumps can raise
31/18 * 16 =248/9 tonnes
=> 1736 tonnes need to be
pumped in : 1739/ (248/9) = 63
tonnes (by 16 pumps)
7 days.
option (4) is correct answer.

Like? Yes (3) | No   

prasad gaikwad   9 years AGO

2170 tonne require 1260 pump-day- hours
1736 x pump-day- hr
x=1008 pump-day-hour
1008/(16*9)=7 days

Like? Yes (2) | No   

Isha Saxena   9 years AGO

18 pumps raise 2170 tonnes in 10 days working 7 hours a day.
in 1 day they raise 2170/10=217 tonnes
in 1 hour they raise 217/7=31 tonnes.
1 pump raises water= 31/18 tonnes.
Now,
16 pumps will roaise=(31/18)*16 tonnes.
working 9 hrs a day they will raise=(31/18)*16*9 tonnes
let the no. of days be d days
thus total=(31/18)*16*9*d
and given total=1736 tonnes
thus dyas, d=1736*18/(9*16*31)=7 days.

Like? Yes (2) | No   

Arifa   9 years AGO

P1*d1*h1/w1=p2*d2*h2/w2. P-no.of pumps,p1=18,p2=16.d-no.of days,d1=10,d2=?.h-no.of hours,h1=7,h2=9.w-work,w1=2170,w2=1736. By solving the above equation, d2=7 days. Ans option 4)7days.

Like? Yes (1) | No   

poojasaisri   9 years AGO

(m1*d1*h1)/w1=(m2*d2*h2)/w2
(18*10*7)/2170=(16*9*d2)/1736
w2=7

Like? Yes (1) | No   

Jaikumar Bhatia   9 years AGO

Ans:
P1=18 pumps
D1=10days
T1=7hrs/day
W1=2170 tonnes

P2=16pumps
D2=Xdays
T2=9hrs/day
W2=1736tonnes


Less pumps,more days(Indirect)
Less water,less days (Direct)
More working hrs (Indirect)

D2=X=(P1*D1*T1*W2)/(P2*T2*W1)
=(18*10*7*1736)/(16*9*2170)
=7
D2=X=7days
so option is (4)

Like? Yes (1) | No   

Deepak   9 years AGO

Work is inversely related to time.
(18*10*7) / (19*9*x) = 2170 / 1736,
x= 7 days

Like? Yes (1) | No   

jaswanth   9 years AGO

in 1 hr 16 pumps raise (2170/1260)16 tonnes of water
1736 tonnes of need --->1736*16*1260/2170=63 hrs
working 9 hours means 7 days required........

Like? Yes (1) | No   

sumit kumar   9 years AGO

comapair it with M1*D1*H1/W1=M2*D2*H2/W2
H2=1736*18*10*7/2170*16*9
=7days

Like? Yes (1) | No   

kanika dhapola   9 years AGO

use formula
M1 D1 T1 W2=M2 D2 T2 W1
D2=(18 *10*7*1736)/(16*9*2170)
D2=7 days Ans

Like? Yes (1) | No   

SURAN PRASAD PENKE   9 years AGO

((2170/(7*10*18))=1unit=1.722
((1736/(x*9*16))=1unit
x=((1736/(1.722*9*16))=7 days

Like? Yes (1) | No   

Abhisheak Kumar Missu   9 years AGO

18 pumps can raise 2170 tonnes of water in 10 days working 7 hours a day.
Hence 18 pumps can raise 2170 tonnes of water in 70 hours.
So 1 pump can raise 1 tonn of water in 70*18/2170
Thus 16 pumps can raise 1736 tonnes of water in 70*18/2170(1736/16)=63 hours
Hence working 9 hour a day it will take 7 days.

Like? Yes (1) | No   

faiz ahmad   9 years AGO

1 pump for 1 day and for 1 hour raises 2170/(18*10*7)
therefore
2170*16*9*x/(18*10*7)=1736
Therefore x=7

Like? Yes (1) | No   

kriti kankariya   9 years AGO

let no. of days to be worked be x
so,(18*10*7)/2170 = (16*9*x)/1736
on solving, x=7days

Like? Yes (1) | No   

vishal barun   9 years AGO

18 pumps,10 days, 7 hours a day loads----2170 tonnes
1 pump, 1 day, 1 hour a day loads----- 2170/18*10*7
16 pump,1 day , 9 hour a day loads--- 31*16*9/18=248
for loading 1736 tonnes of water ,
no. of days required = 1736/248=7.......option 4.

Like? Yes (1) | No   

kiran   9 years AGO

2170/(18*7*10)=1736/(16*9*x)
x=7.
therefore 7days

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prince kumar   9 years AGO

2170/18x70=31/18.
31/18X9X16=248

1736/248=7

Like? Yes (1) | No   

LIKHITA VANJANGI   9 years AGO

[(n1*d1*h1)/w1]/[(n2*d2*h2)/w2]
d2=(n1*d1*h*w2)/(n2*h2*w1)
d2=(18*10*7*1736)/(16*9*2170)
d2=7

Like? Yes (1) | No   

sangam raja   9 years AGO

2170/(18*10*7)=31/18 By one pipe per day in a hour
therefore (31*9*16)/18=31*8 Per day for given task
hence 1736/(31*8)=7 Days

Like? Yes (1) | No   

vimal tiwari   9 years AGO

18 *10*7/2170 = 16*9*d/1736

d=7

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Anand   9 years AGO

less pumps means more days so inverse relation
less quantity of water means less days so direct relation
more working hours per day means less days required so indirect relation
using above relations we have
2170 : 1736
16 : 18 : : 10 : x
9 : 7
solving this we get x= 7 days.

Like? Yes (1) | No   

Surabhi Yadav   9 years AGO

2170=1/p*18*10*7
1/p=31/18
1736=1/p*16*d*9
d=7days

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Anamika Das`   9 years AGO

As the no of days is directly proportional to amount of water and inversely proportional to no of pumps and working hours

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mohan ranga rao   9 years AGO

18*10*7*x=2170
x= work per hour
x=1.72
now
no.of days*9*16*1.72=1736
no.of days=7

Like? Yes (1) | No   

Akshay   9 years AGO

bcz (10d*7h*18)/2170=(?d*9h*16)/1736, so here we need to find day. after that solve the equation i found 7 day...
?d=7.
so ans is 7

Like? Yes (1) | No   

DHEERAJ KUMAR   9 years AGO

18 pumps raise 2170 tonnes in 70 hours
1 hour 18 pumps can raise 2170/70=31 tonnes
1 hour 1 pump can raise 31/18 tonnes
so in 1 hour 16 pumps can raise 31/18*16=248/9
1736 tonnes need to be pumped in=1736/(248/9)=63 tonnes (by 16 pumps)
that means 7 days

Like? Yes (1) | No (1)