A can do a piece of work in 12 days. B is 60 % more efficient to do the same work. If both of the

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28 Jan 2010 man and work

A can do a piece of work in 12 days. B is 60 % more efficient to do the same work.
If both of them work together then the number of days required to do the same work is

OPtion

1) 5/2
2) 24/5
3) 11/3
4) 9/2
5) 7/2
6) 60/13
7) 4
8) 13/8
9) 2
10) 3

Solution

B is 60 % more efficient, therefore total number of days required by him to do the complete work can be
obtained by the formula
12 *1 = 1.6 * x
=> x = 12 / 1.6 = 7.5
When both of them work together, the work of 1 day is (1/12) + (1/7.5) = 13/60
Hence total number of days required are 60/13

Correct Option: 6 Best Solution (7)

Dr.Dipin Singh   15 years AGO

A can do a piece of work in 12 days.

A's one day work = 1/12.
B is 60 % more efficient to do the same work.

B's one day work = (1/12)*1.6 = 2/15

If both of them work together then
their one day work = 1/12 + 2/15 = 13/60

the number of days required to do the same work is 1/( 13/60) = 60/13 ..... option 6

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C.T.Narayanan   15 years AGO

A's 1 day work = 1/12
B's 1 day work = 1/12 + 60% of 1/12 = 2/15
(A+B)'s 1 day work = 1/12 + 2/15 = 13/60
Work can be completed in 60/13 days.

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Dimple   15 years AGO

A and B 's one day work = (1/12) + (1/12)*1.6 = 13/60

so they both together will complete the work in 60/13 days.

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susmit   15 years AGO

per day A can do 1/12th work. B can do 13*1/12th work. So both of them combiningly can do 2.6/12th work. so total no of days taken is 12/2.6=60/13

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Dimple   15 years AGO

A's one day work = 1/12
B's one day work = ( 1/12)* 1.6 = 2/15

(A+B)'s one day work = 1/12 + 2/15 = 13/60

so they will complete one work in 60/13 days.

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Mehul MKDP   15 years AGO

0.21667

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Sukham   15 years AGO

one day work of A+B = (1/12)( 1+1.6) = 2.6/12 = 1.3/6 = 13/60

so A and B together will complete the work in 60/13 days

Like? Yes (1) | No