Here a = 27 and d = 24-27 = -3 (Series is AP)
Let nth tern of the given AP be the first negative tern
Then Tn < 0
=> (a + (n-1)d) < 0
=> (27 + (n-1)(-3)) < 0
=> (27 - 3n + 3) < 0
=> 30 - 3n < =
30 < 3n
3n > 30
n > 10
Therefore n = 11
Hence, the 11th tern is the first negative tern of the give AP.
Option 4)
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suresh
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