Mohit has two coins, one of Rs. 1 denomination and the other of Rs. 2 denomination. He tosses the two coins simultaneously. What is the probability that he gets at least one head?
We write H1 for head and T1 for tail of Rs. 1 coin. We write H2 for head and T2 for tail of Rs. 2 coin.
Thus, the possible outcomes are H1H2, H1T2, H2T1, T1T2
All the four outcomes are equally likely. Let the event getting at least one head be denoted by A.
Now, the three outcomes H1H2, H1T2, H2T1 favour the happening of the event A.
Therefore, P(A) = 3/4
Hence, the probability that Mohit gets at least one head is 3/4.
Option 7)