21 banana trees, 42 grapes trees and 56 papaya trees have to be planted in rows such that each row c

M4maths Previous Puzzles

20 Apr 2016 Minimum number of rows

21 banana trees, 42 grapes trees and 56 papaya trees have to be planted in rows such that each row contain the same number of trees of one variety only. Minimum number of rows i which the above trees may be planted is

OPtion

1) 3
2) 10
3) 13
4) 15
5) 16
6) 17
7) 18
8) 20
9) 22
10)24

Solution

HCF of 21, 42, 56 = 7
Number of rows of banana trees, grapes trees and papaya trees are
21/7 = 3
42/7 = 6
56/7 = 8
Therefore Required number of row
3+6+8 = 17
Option 6)

Correct Option: 6 Best Solution (14)

priti kiran   8 years AGO

only 7 is divides all 21,42 and 56.
21 can be in 3 rows- 21/7
42 can be in 6 rows- 42/7
56 can be in 8 rows- 56/7
total rows 8+6+3=17

Like? Yes (7) | No (1)  

dev   8 years AGO

find the HCF of 21,42,56 == 7
so each row contains 7 trees of one type
total no of rows = (21/7) + (42/7) + (56/7) = 17

so (6) is option

Like? Yes (2) | No   

viswambher   8 years AGO

Since the hcf of 21,42 & 56 is 7.
Each row is filled with 7 trees of 1 variety.
Therefore there is a total of 3 rows of banana trees & 6 rows of grape trees & 8 rows of papaya trees.

Max no. of rows is (8+6+3)= 17

Like? Yes (1) | No   

Divesh Singla   8 years AGO

3*7=21
6*7=42
8*7=56

Like? Yes (1) | No   

madanpal vishwakarma    8 years AGO

we have 21 banana , 42 grapes and 56 papaya tree

rule1 : need to plant same no of tree in each row

rule2 : each row must havesame kind of trees .

so we need a max common value which divide all three values

i got 7 which can divide all three qty completly

so we have 21/7 = 3 rows for banana
42/7 =6 rows for grapes
56/7=8 rows for papaya
so we have 3+8+6=17 rows


so option 6 is correct .

Like? Yes (1) | No   

deepan   8 years AGO

Hcf :21,42,56=7
banana tree rows=3
grape rows=6
papaya rows=8

Like? Yes (1) | No   

RISHABH   8 years AGO

Take H.C.F of 21, 42, 56 = 7
So, 7*3=21
7*6=42
7*8=56
So, total no. of rows = 3+6+8=17

Like? Yes | No   

Lenin   8 years AGO

HCF of 21, 42, 56 is 7.
so, each row should have 7 trees.
so, the total no. of rows = 3 + 6 + 8 = 17 .
answer is option 6.

Like? Yes | No   

karthiga   8 years AGO

To find the HCF of 21, 42, 56 is 7;
21banana tree is planted in 3 rows;
42 grapes trees are planted in 6 rows;
56 paaya trees are planted in 8 rows;
so totally 3+6+8=17 rows.

Like? Yes | No   

Imtha thullah   8 years AGO

If each row have 7 rows, then
banana tree have 21/7, 3 rows and
grapes tree have 42 / 7, 6 rows and
papaya tree have 56 / 7, 8 rows. Therefore,
total no of rows = 3 + 6 + 8 = 17.
option : 6 ).

Like? Yes | No   

rydham goyal   8 years AGO

the lowest no of rows = total number of banana trees + total number of grapes trees + total number of papaya trees / highest number of trees in each row

therefore the highest number of tree in each row = hcf(21 , 42 , 56)
=7

therefore lowest numbeer of trees = 21+42+56/7
= 119/7
= 17

Like? Yes | No   

shubham sethiya   8 years AGO

21- bananas 7 for each row i.e 3 rows
42- grapes 7 for each row i.e 6 rows
56 papaya 7 for each row i.e 8 rows

so total no. of rows = 17


hint:- HCF of 21 42 and 56 is 7.

Like? Yes | No   

Maji   8 years AGO

If each tree have 7 rows, then
banana tree have 21/ 7, 3 rows and
grapes tree have 42 / 7, 6 rows and
papaya tree have 56 / 7, 8 rows.
Therefore,
total no of rows = 3 + 6 + 8 = 17.
option:6).

Like? Yes | No (1)  

Nandkishor jaiswal   8 years AGO

lcm of all tree(21,42,56)=7
so total number of rows=(21/7)+(42/7)+(56/7)
=17 rows

Like? Yes | No (2)