A brooch is made with silver wire in the form of a circle with diameter 35 mm. The wire is also used

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29 Apr 2016 Total length of the silver wire

A brooch is made with silver wire in the form of a circle with diameter 35 mm. The wire is also used in making 5 diameters which divide the circle into 10 equal parts. Find the total length of the silver wire required.

OPtion

1) 185 cm
2) 38 cm
3) 285 mm
4) 174 mm
5) 196 mm
6) 58 cm
7) 84 cm
8) 265 mm
9) 325 mm
10)125 mm

Solution

Diameter of the circle = 35 mm
Therefore radius r = 35/2 mm
Therefore Total length of wire required = Length of wire required for making 5 diameter + Length of wire required for making the perimeter of circle
= 5 * 35 * 2*Pi*35/2 mm
= 175 + 22/7*35 mm
= 285 mm
Option 3)

Correct Option: 3 Best Solution (17)

ABHINAV PUSHPAM   8 years AGO

Circumference = 2pir = 35pi = 110 mm

Wire required for 5 diameters = 35 x 5 = 175 mm

Total length of wire = 110 + 175 = 285 mm

Option 3)

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Aakash Beniwal   8 years AGO

wire used in circle= 2* 22/7 *radius = 2 * 22/7 * 35/2 =110mm
wire used in diameter = 35 * 5= 175 mm
total wire used = 110 + 175 = 285 mm

Like? Yes (3) | No   

Nandkishor jaiswal   8 years AGO

given that 2*r=35
so, circumference will be 22/7*35=110mm
so total length required=35*5+110=285mm

Like? Yes (3) | No   

MRITUNJAY   8 years AGO

Circumference = 2?r = 35? = 110 mm

Wire required for 5 diameters = 35 x 5 = 175 mm

Total length of wire = 110 + 175 = 285 mm
option 3

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sumant kumar   8 years AGO

silver wire used to make brooch=(22/7 )*35 =110mm
wire used in 5 diameter=5*35 =175mm
silver wire required=110 + 175
= 285mm

Like? Yes (2) | No   

Aman Shrivastava   8 years AGO

silver wire used to made a brooch= 22/7*35=110mm
wire used in 5 diameter =5*35=175mm
total wire used =110+175
=285mm

Like? Yes (2) | No   

RAHUL KUMAR   8 years AGO

Number of diameters = 5
Length of diameter = 35mm
∴ Radius = 35/2 mm
Total length of silver wire required = Circumference of the circle + Length of 5 diameter = 2π r + (5×35) mm = (2×22/7×35/2) + 175 mm = 110 + 175mm = 285 mm
option (3).

Like? Yes (1) | No   

Mridula Shaw   8 years AGO

Radius=35/2 mm
Thus,perimeter=2*22*35/(7*2)=110 mm(wire for circle)
One diameter=35 mm
Thus,
5 Diameters=5*35=175 mm (wire for diameters)
Thus,
Total length of wire=110+175=285 mm

Like? Yes (1) | No   

Imtha thullah   8 years AGO

Total length of wire required will be the length of 5 diameters and the circumference of the brooch.
Radius of circle= 35/2 mm.
circumference of brooch= 2*22/7*r,
= 2*22/7*35/22,
=110.
length of the wire=110+(5*35),
=110+175,
=285 mm.
option : 3 ).

Like? Yes (1) | No   

Swetha Gottimukkula   8 years AGO

perimeter of the circle is 2*pi*r
so 2*22/7*35mm/2=110mm
the wire used to make circle 10 parts is 5*33mm=175mm
so 175+110=285mm
so the wire used is 285mm

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Ankita   8 years AGO

Circumference = 110 mm
5 Daimeters = 175 mm
Total wire = 110+175 = 285mm
Option 3

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Pooja Priti   8 years AGO

perimeter of circle=110
5 diameter=175
total wire used=175+110=285mm

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Vaishali Jain   8 years AGO

total wire = circle + 5 diameter
= 2*pi*r + 5*d
= ( 2*22/7*35/2 ) + 5*35
= 285

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Anup Sahay   8 years AGO

circumference of brooch = 2*3.14*(35/2)=109.9
5 diameters sum=5*35=175
total wire required= 175+109.9=284.9
so required wire =285mm

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DEBASIS SINGHA   8 years AGO

5 diameters of length 35mm,so total length= 5*35=175mm.
nw,circumfrence of the circle= 22/7*35=110mm.
so total length=175+110=285mm.

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Akshat Sood   8 years AGO

Circumference=2*22*35/2*2*7= 110mm
as it is used to make 5 diametres =35*5=175mm
total length becomes 285mm

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Maji   8 years AGO

Total length of wire required will be the length of 5 diameters and the circumference of the brooch.
Radius of circle= 35/2 mm.
circumference of brooch= 2*22/7*r,
= 2*22/7*35/22,
=110.
length of the wire=110+(5*35),
=110+175,
=285 mm.
option : 3 ).

Like? Yes | No (1)