A dinner party is to be fixed for a group consisting of 100 persons. In this party, 50 person do not

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11 May 2016 Number of person

A dinner party is to be fixed for a group consisting of 100 persons. In this party, 50 person do not prefer Veg, 60 prefer Non-veg and 10 do not prefer either Non-veg or Veg. The number of persons who prefer both Veg and Non-veg is

OPtion

1) 20
2) 35
3) 50
4) 55
5) 70
6) 60
7) 40
8) 30
9) 10
10)None of these

Solution

Let A be the set of persons who prefer Veg and B be the set of persons who prefer Non-veg.
Solve by using set theory
n(A U B) = 100 - 10 = 90
n(A) = 100 - 50 = 50
and n(B) = 60
Therefore
n(A Inter B) = n(A) + n(B) - n(A U B)
= 50+60 - 90) = 20
Ans - 20
Option 1)

Correct Option: 1 Best Solution (4)

Lenin   8 years AGO

person do not prefer either veg & non-veg = 10.
persons do not prefer veg = 50 = (person only prefer non-veg + do not prefer either veg or non-veg)
==> 50 = X+10. X = 40.
person only prefer non-veg = 40
person prefer non-veg = 60.
so, person prefer both = 60 - 40 =20.
option 1.

Like? Yes (2) | No   

Mukund Manohar   8 years AGO

Let x be the number of person who prefer both.
60 + 50 - x = 90
So, x=20

Like? Yes (5) | No (3)  

Hareesh    8 years AGO

There is given that 10 of them will not prefer either of the two veg or non veg..so among 100 people there is 90 people is who prefer either veg or non veg...
Take v= veg N,v = Non veg
v=50,Nv=60,v(or)Nv =90,
==>v(and)Nv=v+Nv-v(or)Nv
=50+60-90
=20.

Like? Yes (2) | No (1)  

Abdul rahiman c m k   8 years AGO

number of person who prefer eighter veg or non veg=90

let A prefer veg and B non veg
then the the mumber of person who prefer both veg & non veg = AUB =(50+60)-90 =20

Like? Yes (1) | No (1)