The difference between simple interest and compound interest on a sum for 2 years at 8%, when the in

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10 Jun 2016 Difference in 2 years

The difference between simple interest and compound interest on a sum for 2 years at 8%, when the interest is compounded annually is Rs.16. If the interest were compounded half yearly, the difference in 2 years would be nearly.

OPtion

1) Rs.16
2) Rs.9
3) Rs.36.20
4) Rs.26.60
5) Rs.16.80
6) Rs.9.80
7) Rs.21.85
8) Rs.18.50
9) Rs.24.64
10)None of these

Solution

SI on (S.I. for 1 year) = Rs.16
SI on (P*1*8/100) = Rs.16
SI of P = Rs.200
Therefore
P = 100*200/8*1 = 2500
Amount for 2 years compounded half-yearly
= 2500*(1+ 4/100)^4 = 2924.64
CI = 424.64
SI = 400
CI - SI = 24.64
Option 9)

Correct Option: 9 Best Solution (11)

ABHINAV PUSHPAM   8 years AGO

Answer: Rs.24.64 

Explanation:

For 1st year S.I =C.I.

Thus, Rs.16 is the S.I. on S.I. for 1 year, which at 8% is thus Rs.200

i.e S.I on the principal for 1 year is Rs.200

Principle = ? = Rs.2500

Amount for 2 years, compounded half-yearly

?

C.I = Rs.424.64

Also, ?

Hence, [(C.I) - (S.I)] = Rs. (424.64 - 400) = Rs.24.64.

Option 9)

Like? Yes (2) | No   

Mukund Manohar   8 years AGO

For 1st year SI=CI
Rs 16 is the SI on SI for 1 year which at 8% is Rs 200
P=(100*200)/(8*1) = 2500
Amount for 2 years compounded half yearly
=2500*(1+ 4/100)^4
=2924.64
CI = Rs 424.64
SI = (2500*8*2)/100
=Rs 400
CI-SI = 424.64-400
=Rs 24.64

Like? Yes (2) | No   

Pradyumna K S   8 years AGO

For 1st year S.I =C.I.
Thus, Rs.16 is the S.I. on S.I. for 1 year, which at 8% is thus Rs.200
i.e S.I on the principal for 1 year is Rs.200
Principle = 100*200/8 = Rs.2500
Amount for 2 years, compounded half-yearly
=2500*(1+4/100)^4= 2924.64
C.I = Rs.424.64
Also, SI= 2500*8*2/100 = 400
Hence, [(C.I) - (S.I)] = Rs. (424.64 - 400) = Rs.24.64

Like? Yes (1) | No   

rahul Tiwari   8 years AGO

firstly ci-si =16so .64=16then p=2500;
now if we take ci half yearly then total interest is 424.64

Like? Yes (2) | No (1)  

vikas rana   8 years AGO

r= 8%,n=2
first we need to calculate principle amount
C.I -S.I=16
=> P[1+r/100]^n -P-S.I=16
=> P=2500
now in question it is given that interest were compounded half yearly
so the difference in 2 years will be
r=8/2=4 and n=2*2=4
find C.I -S.I
and the answer would be Rs. 24.64

Like? Yes (2) | No (2)  

Prateek Dhir   8 years AGO

Let principal be x.
SI=x*8/100*1=4x/25
CI=104x/25
16=CI-SI
x=2500
CI half-yearly=x(1+8/200)^2*2-x=424.64
ans=424.64-400=Rs24.64

Like? Yes (1) | No (1)  

manoj    8 years AGO

solve

p(108^2-100^2)/100^2-p*8*2/100=16

finding::: p(104^4-100^4)/100^4-p*4*4/100=24.64

Like? Yes | No   

Ritika   8 years AGO

P{(r/100)}^2=16
P=2500
hence by formula we get Rs24.64

Like? Yes | No   

Bharath daniel   8 years AGO

Principle=2500
Ci=424.6464
Si=400
So diference is 24.6464

Like? Yes (1) | No (1)  

ch.keerthana   8 years AGO

for 1st year S.I=C.I
RS.16 for 1 year, which is at 8% is thus RS.200
i.e. , S.I on principle for 1 year is RS.200
principle=((100*200)/(8*1)) =RS.2500
amount for 2years, compounded half-yearly
=RS(2500*(1+4/100)^4)
=RS.2924.64
C.I=RS.424.64
S.I=RS.((2500*8*2)/(100))
=RS.400
((C.I)-(S.I))=RS.(424.64-400)
=RS.24.64
so option 9 is correct

Like? Yes | No (1)  

N.Vennela Rani   8 years AGO

Given that:r=8%,n=2yrs,(P(1+(8/100))^2-p)-((px2x8)/100)=16=>P=2500,SI=(pxtxr)/100=400, CI=p(1+(r/200))^2n-p=424.64....difference=424.64-400=24.64

Like? Yes | No (2)