If in coded language RAMESH = 235 SHIVAM = 363 MANISH = 291 Then SANJAY = ?

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27 Sep 2016 Coded language

If in coded language
RAMESH = 235
SHIVAM = 363
MANISH = 291
Then
SANJAY = ?

OPtion

1) 184
2) 426
3) 192
4) 356
5) 426
6) 291
7) 176
8) 364
9) 375
10)198

Solution

A(1), B(2), C(3), D(4), E(5), F(6), G(7), H(8), I(9), J(10), K(11), L(12), M(13), N(14), O(15), P(16), Q(17), R(18), S(19), T(20), U(21), V(22), W(23), X(24), Y(25), Z(26)
RAMESH = R*A + M*E + S*H = 18*1 + 13*5 + 19*8 = 18+65+152 = 235
SHIVAM = S*H + I*V + A*M = 19*8 + 9*22 + 1*13 = 152+198+13 = 363
MANISH = M*A + N*I + S*H = 13*1 + 14*9 + 19*8 = 13+126+152 = 291
Similarly
SANJAY = S*A + N*J + A*Y = 19*1 + 14*10 + 1*25 = 19+140+25 = 184

Option 1)

Correct Option: 1 Best Solution (16)

nimisha gupta   8 years AGO

S=19
A=1
N=14
J=10
A=1
And y=25
So 19*1+14*10+1*25
=184

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manish sharma   8 years AGO

ramesh =(18*1)+(13*5)+(19*8)=235
shiVam = (19*8)+(9*22)+(1*13)=363
manish = (13*1)+(14*9)+(19*8)= 291
sanjay= (19*1)+(14*10)+(1*25)=184

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prakash sharma   8 years AGO

according to Weighted code like
RAMESH (18,1,13,5,19,8)=>18*1+13*5+19*8=235
so same as
SANJAY(19,1,14,10,1,25)=>19*1+14*10+1*25=184(option 1)

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Siva   8 years AGO

18×1+13×5+19×8=235,
19×8+9×22+1×13=363,
13×1+14×9+19×8=291,
As like this
19×1+14×10+1×25=184.

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Geetha   8 years AGO

A(1)B(2)....Z(26).
S(19)A(1)N(14)J(10)A(1)Y(25)
Split into three sets,perform mulitipication with in the set and then perform addition with the sets
SA,NJ,AY
(19*1)+(14*10)+(1*25)=184

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MAHESHKUMAR KOTAMBRI   8 years AGO

s=19, a=1,n=14,j=10,y=25
SA+Nj+ay=19+140+25=184

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y.nikhil   8 years AGO

s=19, a=1, n=14, j=10, a=1, y=25
s*a=19*1=19
n*j=14*10=140
a*y=1*25
19+140+25=184

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Kunal nemu   8 years AGO

we get in the position of word...
RAMESH = 18*1+13*5+19*8 =235
same MANISH =13*1+14*9+19*8=291
same SANJAY = 19*1+14*10+1*25= 184
so the answer is 184

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dattatrayareddy   8 years AGO

first to multiply and next two multiply and next two multiply and add the three values we get the answr

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rajshree dadhich   8 years AGO

consecutive multiplication of the numbers and then add all the numbers

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chary   8 years AGO

Multiply each two letter"s place values and add them to get the answer

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Akhila pathivada   8 years AGO

RAJESH= 18*1+13*5+9*8
=235
Likewise
SANJAY=19*1+14*10+1*25
=184

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SATHEESH V   8 years AGO

(18×1)+(13×5)+(19×8)=235
(19×8)+(9×22)+(1×13)=363
Similarly
(19×1)+(14×10)+(1×25)=184

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Satishbabu   8 years AGO

RAMESH -> 18 1 13 5 19 8 -> 18*1+13*5+19*8 = 235
SHIVAM -> 19 8 9 22 1 13 -> 19*8+9*22+1*13 = 363
MANISH -> 13 1 14 9 19 8 -> 13*1+14*9+19*8 = 291

=> SANJAY = 19 1 14 10 1 25 -> 19*1+14*10+1*25 = 184

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Aakash Beniwal   8 years AGO

logic
take A=1, B=2 ,C=3, ... R=18,S=19, ... SIMILARLY
for RAMESH
18, 1 , 13 ,5 , 19 ,8
take two at once and multiple them and add all result like:>
(18 *1) + (13*5) +(19*8) = 18+65+152 = 235
similarly solve for SANJAY
my answer is 184

Like? Yes | No (1)  

Kshitij   8 years AGO

RAMESH = (18*1)+(13*5)+(19*8) = 235
SHIVAM = (19*8)+(9*22)+(1*13) = 363
MANISH = (13*1)+(14*9)+(19*8) = 291
So, SANJAY = (19*1)+(14*10)+(1*25) = 184

Like? Yes | No (1)