G.S.Kantharao   8 years AGO

Reletive speed=50+4=54Kmph.
Speed per second is =54*(5/18) = 15Mts./Sec
Time taken to cross = Distance/Speed = 270/15 = 18 Sec.
Hence my choice is 8.

Like? Yes (4) | No (1)  

Shavy khanna   8 years AGO

Length of the train=270m
Speed of the train=50kmph
Speed of man=4kmph
Relative speed=50+4=54kmph
Speed in m/s=54*5/18=15m/s
(Length of train=distance)
Time =distance/speed
Time=270/15=18 sec(Option 8).

Like? Yes (3) | No (2)  

Nishu Kumari   8 years AGO

T= D/S
Man coming from opposite direction so speed will be added 50+4=54 and it should be converted in sec also

So ans is----
270*18/54*5=18 sec

So ns is 18 sec.

Like? Yes (2) | No (2)  

Nandini JB   8 years AGO

relative speed=50+4=54km/h= 54*1000/(60*60)=15m/s
time=distance/speed=270/15=18sec

Like? Yes (1) | No (1)  

amit dixit   8 years AGO

50+4=54
54*5/18=15

270/15=18 sec

Like? Yes (1) | No (1)  

Ajit Chaudhary   8 years AGO

Relative Speed = 54 km/h = 15 m/sec
Length of train/ Distance = 270 m
Therefore, Time = 270/15 sec = 18 sec
Correct option (8).

Like? Yes | No   

Anusha Mukka   8 years AGO

opposite direction =50+4=54
time =d/s
time=270/54*5/18. (5/18 is to convert kmph into msec)
=18 sec

Like? Yes (1) | No (1)  

umend   8 years AGO

Distance travelled = 270mt
Relative speed = (50+4)=54km/hr=15m/s
Time taken= 270/15
=18s (ans)

Like? Yes (1) | No (1)  

Sudhakarshona   8 years AGO

Speed of the train relative to man = (50+4)kmph
54 kmph = 54*5/18 m/s = 15 m/s
Time taken by the train to cross the man = Time taken by it to cover 270 m at 15 m/sec = 270/15 = 18 seconds

Like? Yes (1) | No (1)  

Nitish kesarwani   8 years AGO

since man move oppt s=50+4=54km/h
change m/s =5/18*54=15m/s
t=d/s 270/15=18sec

Like? Yes (1) | No (1)  

nimisha gupta   8 years AGO

Relative speed of train and man=50-(-4)
=54kmph
Time =270*18/54
=18 sec

Like? Yes (1) | No (1)  

JAYA TRIPATHI   8 years AGO

let the speed of train is s1 and speed of man is s2
and length of train is l1 , length of man is l2
therefore,
s1+s2 = l1+l2/t
(50+4)*5/18 = 270+0/t
54*5/18 = 270/t
=> t = 270/15
t = 18sec
so the train will cross the man in 18 sec. option(8).

Like? Yes (1) | No (1)  

Nwobi Chibuzor    8 years AGO

Time taken for the train to cross a man in the opposite direction is = train length / speed of train + speed of man

Time taken = 270s / 50kmph + 4kmph; = 270s / 54kmph

Change 54kmph to mps;
54 × 1000/36000 = 15mps

Now we can divide;
Time taken = 270m ÷ 15mps = 18s.
Ans = 18s

Like? Yes (3) | No (3)  

Gurpreet Kaur   8 years AGO

time=distance /speed
distance= length of train=270m
speed of train =50kmph
speed of man=4kmph
relative speed =50+4
(in opposite direction )
=54kmph=54×5/18mps

time = 270m/(54*5/18)m/sec
time=18sec

Like? Yes (1) | No (1)  

Parnab Ghosh   8 years AGO

Relative speed= (50+4)*5/18= 15 m/sec
Distance= 270 m
Time= 270/15 = 18 sec

Like? Yes (1) | No (1)  

sainath   8 years AGO

Distance,D=270m
total speed,S=50+4=54kmph=18m/s
Time = Distnace/speed
=270/15
=18m/s

Like? Yes (1) | No (1)  

Samanvya garg   8 years AGO

train speed is 13.88 m/ sec
and man speed is 1.11 m/ sec
using concept of relative velocity if they are in opposite direction we have to add them
distance( length of train)= speed* time;
270/15=18 sec approx

Like? Yes (1) | No (1)  

Samruddha   8 years AGO

relative speed=50+4=54km/hr.
In m/s=54*5/18=15m/s
time=270/15=18sec

Like? Yes (1) | No (1)  

Dinesh Sharma   8 years AGO

Time taken = Length of Train / Total Speed
Since man coming from opposite direction, So train speed and man speed are combine i.e. total speed = (50+4)kmph = 54kmph = 54*(5/18) mps=15mps

i.e. t = 270m / 15mps = 18sec

Like? Yes (1) | No (1)  

sanjeet kumar   8 years AGO

Net speed = 54kmph
= 15 mps
Distance = 270 m
Time = 270/15 = 18 sec

Like? Yes (1) | No (1)  

ujjawalkumar    8 years AGO

Add the speed of both the man and the train then use the formula od speed and time to get the time .

Like? Yes (1) | No (1)  

santosh shah   8 years AGO

realtive sped=50+4=54kmph
54*5/18=15

t=270/15=18sec

Like? Yes (1) | No (1)  

sonia   8 years AGO

270m=.270km
t=d/s
=.270/54
=1/200h
1/200*3600s=18sec

Like? Yes | No   

Ashish Bhatt   8 years AGO

train speed=50Kmph
man's speed=4 KmPh
relative speed=50+4 KMPH(as they are moving in opposite direction)

train length=270M

convert 54Kmph to m/sec
54*5/18=15m/sec

270/15=18sec

Like? Yes | No   

vikash thakur   8 years AGO

speed =speeed of train +man speed
=>50+4 = 54
convert in m/sec
multiply with 5/18
that is 15m/sec.
divide 270 by 15 ,we get the answer

Like? Yes | No   

PODETI SRINIVAS GOUD   8 years AGO

Average speed=50+4=54kmph
=54*5/18=15m/s
time=distance/speed
=270 m/15m/s=18sec

Like? Yes | No   

Raj   8 years AGO

The length of train = 270m (given)
So it has to travel a total distance of 270m
So, d=270m

Also the train and man are travelling in opposite direction
So, their relative speed will be 50+4 = 54 km/hr
=54*(5/18)m/s
=15m/s

Now, t=d/s
we get t=270/15
t=18 sec

So option 8 is correct

Like? Yes (1) | No (1)  

PRADEEP SINGH   8 years AGO

Total dist: 270m
speed of train: 50kmph
speed of man: 4kmph
relative speed=speed of train + speed of man=50+4=54kmph
speed in m/s=54*(5/18)=15mps
total time=distance/speed
=270/15=18 mps

Like? Yes | No   

gulshan   8 years AGO

s=d/t
(50+4)=270/t
t=270/54
t=5*18/5
t=18sec

Like? Yes | No   

Mohammad Obaid Ullah   8 years AGO

speed of train relative to man =(50+4)kmph
=(54*5/18)m/sec =15m/sec
therfore time taken by train to cross the man = time taken by it to cover 270 m at at 15 m/sec = 270/15
=18 sec

Like? Yes | No   

kondapuram tirumalreddy   8 years AGO

relative speed of train w.r.t man = (4+50)kmph= 54kmph

speed in m/s= 54*(5/18) = 15 m/s

Like? Yes | No   

Sabarisan   8 years AGO

speed=15m/s due to opp direction
distance=270m
so... Time=18s

Like? Yes | No   

Vijay Kumar   8 years AGO

we know that,d=s/t
so,in opposite direction,50+4=54kmph
in meters,54*(5/18)=15m.
therefore,t=d/s=270/15=18sec.

Like? Yes | No   

Avinash Jha   8 years AGO

t=l/s
s=speed of train+ speed of man (both are moving in opposite direction)
l= length of train
t=270/15
=18sec

Like? Yes | No   

manish sharma   8 years AGO

Speed of train = 50kmph
speed of person =4kmph
adding these both to get total speed of a object to cross other = 50+4=54kmph
converting 54kmph in mps = 15mps
now to cross train of 270m length
270/15= 18s.

Like? Yes | No   

Ankita Sharma   8 years AGO

Given length,i.e.
distance=270m
Speed of train =50kmph
=(25/9)MPs
Speed of man(in opp. direction)=4kmph
=(10/9)mps
Hence total speed=(25/9-10/9)=15/9
Since speed=distance/time
Time=distance/speed
=270/(15/9)
=18sec

Like? Yes | No   

phanikumar   8 years AGO

The relative speed=50+4=54kmph

54*5/18=15m/sec

t=d/s
t=270/15=18sec

Like? Yes | No   

manik garg   8 years AGO

relative speed=50+4
=54kmph
=54*(5/18)
=15mps
so time taken=270/15
=18sec

Like? Yes | No   

Rajendra Sinha   8 years AGO

50+4=54
54k mtr in 3600 sec
270 mtr in (3600*270)/54000= 18 sec
A: 18 sec

Like? Yes | No   

ADITI GOEL   8 years AGO

speed of train=50kmph=125/9 mps
speed of man in the direction of train moving=-4kmph=-10/9 mps
relative speed=(125+10)/9=15 mps
from s=ut+1/2 at^2
we have......
270=15*t
t=270/15=18 sec

therefore,answer is 8) i.e 18 sec

Like? Yes | No   

RITIK RANJAN   8 years AGO

given, length of the train=270 m
speed of the train=50 kmph
speed of the man=4 kmph
now, the man is coming from opposite direction.
thus, speed adds up. hence, total speed becomes(50+4)=54 kmph.
now, we have to find the time?
so, we know the formula: time=distance/speed
putting values in the formula we get:
time=270(length of the train i.e; distance)/15=18 sec. which is our required answer.
note:
we have to convert 54 kmph in to m/s.
thus, 54 kmph=54*5/18=15 m/s

Like? Yes | No   

Narasimha   8 years AGO

V=d/t...then t=d/v..relative velocity 48+6=54,..t=270/15..=18

Like? Yes | No   

JENSI KARUNYA.S   8 years AGO

length of the train=270m
train and the man are traveling in opposite direction
So,speed = (50+4)*5/18
time=distance/speed
T=270/(54*5)/18
T=18sec
option 8) 18 sec is correct answer.

Like? Yes | No (1)  

Amarnath Kumar Upadhyay   8 years AGO

relative speed =50+4 km/h
so time taken to cross = (270/1000)*(1/54)*3600=18sec

Like? Yes | No (1)  

Suraj Kesharwani    8 years AGO

50+4=54kmph
54*5/18=15
270/15=18sec

Like? Yes | No (1)  

haritha reddy   8 years AGO

relative velocity=54kmph=15mps
velocity=distance/time
time=distance/velocity
time=270/15=18

Like? Yes | No (1)  

Hanish Savla   8 years AGO

length of train=270
relative speed= 50+4= 54kmph
=54*10/36=15mps

time=distance/speed=270/15=18

Like? Yes | No (1)  

ANAND MOHAN RAI   8 years AGO

relative velocity of train=54 kmph=54*5/18=15 m/s
hence time=270/15=18 sec

Like? Yes | No (1)  

sarthakgoel   8 years AGO

both are in opp dir so speed will add and convert into m/sec then use s=d/t

Like? Yes | No (1)  

heena   8 years AGO

given: length=270m
speed of train=50km/hr
i.e speed of train=125/9 m/sec
speed of man= 4km/hr
i.e speed of man= 10/9 m/sec
t=d/s
t=(270+0)/(125/9+10/9)
t=18seconds

Like? Yes | No (1)  

Prasad Kale   8 years AGO

Used the formula
Time= Distamce/ speed
so, first convert Speed from km/he to m/sec by multiplying 5/18.
and then rest substitute the values

Like? Yes | No (1)  

shamil muhammed   8 years AGO

both train and moves in opposite direction.so relative speed of train wrt man is 50+4=54kmph
54*5/18=135/9 mps
time taken is270/(135/9)=18sec

Like? Yes | No (1)  

somesh choudhary   8 years AGO

50+4 total relative speed = 54 kmph
in m/s = 15 m/s and total distance =270
so time = 18 sec

Like? Yes | No (2)  

SADDAM   8 years AGO

Time=distance/(relative speed)
distance=270m
relativespeed=50-(-4) kmph=54*5/18mps
=15mps
Hence
time=270/15=18sec

Like? Yes | No (2)  

Venkatesh Rajendran   8 years AGO

Distance=Speed*time
Relative speed= 50+4=54kmph
0.27/54=0.005hrs
0.005*3600=18 secs

Like? Yes | No (2)  

krishna   8 years AGO

train in opposite direction so relative speed is 54kmph in Mt/sec=15m/s then time=distance/speed=270/15=18sec.

Like? Yes | No (2)  

yerra anitha   8 years AGO

here, we need to find the time ie.,
T=D/S
here distance= the length of the train=270.
speed= the speed of the train+the speed of the man ( Bcz opposite direction).
so we have T=(270ms)/(54kh)
here we need to convert 54kh into ms by multiplying
54*(5/18)=15.
now T= 270ms/15ms=18ms time.

Like? Yes | No (2)  

Sachin Kumar   8 years AGO

Speed =54*5/18
distance =270
time =distance /speed
time =270/15
time = 18 second

Like? Yes | No (2)  

suma priya   8 years AGO

in opp direction= length of train=speed of train *speed of man*time
time = 270/(50+4)*5/18
= 270/15
18sec

Like? Yes | No (2)