What is the next number of the following sequence 9, 54, 243, 927, 3645, ?,...

Lakshmi Narayanan.k   8 years AGO

9,54,243,927,3645,?
The given numbers are divisible by 9.
The option 3 is the only number which is divisible by 9.

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G.S.Kantharao   8 years AGO

9,54,243,927,3645 all are multiples of 9.
In the given 13122 is the only multiple of 9.
Hence my choice is 3.

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Mathi Vanan P   8 years AGO

9=9
5+4=9
2+4+3=9
9+2+7=18.(1+8=9)
3+6+4+5=18(1+8=9)
therfore,
1+3+1+2+2=9
so the answer is 13122
option 3

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Samjukta Das   8 years AGO

In the series all the numbers are divisible by 9 and in the options 13122 is the only number which is divisible by 9 so 13122 is the answer

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Arshi   8 years AGO

3*1(3)^1=3
3*2(3)^2=54
3*3(3)^3=243
3*4(3)^4=972
3*5(3)^5=3645
3*6(3)^6=13122

Like? Yes (3) | No (2)  

P.V.Vishnu Prasanth   8 years AGO

add the digits
it should be divisible by 9
1+3+1+2+2=9

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Kiruthika   8 years AGO

3^2*1=9
3^3*2=54
3^4*3=243
3^5*4=927
3^6*5=3645
3^7*6=13122

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Mukund Manohar   8 years AGO

Digital root of every number of the sequence is 9.And there is only one option whose digital root is 9,i.e. 13122

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siri   8 years AGO

series is n*3^n+1
so,6th term is 6*3^7 =13122
note:4th term here is 972 not 927

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Shaily Agarwal   8 years AGO

sum of all digits of 13122 is 9 .
sum of all digits oc each number of sequence also 9

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Nandini JB   8 years AGO

0+9=9
5+4=9
2+4+3=9
9+2+7=18=1+8=9
3+6+4+5=18=1+8=9
1+3+1+2+2=9

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Shweta   8 years AGO

0+9=9
5+4=9
2+4+3=9
9+2+7=9
3+6+4+5=9
1+3+1+2+2=9

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Dev   8 years AGO

The given sequence contains the nos which r divisible by 3 ..So frm the options 3 and 6 satisfies it..so d nxt no ll b 13122

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T Purushotham   8 years AGO

3^2*1=9
3^3*2=54
3^4*3=243
3^5*4=972
3^6*5=3645
3^7*6=13122

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T SIVAPRAKASH   8 years AGO

9
5+4=9
9+2+7=18=1+8=9
3+6+4+5=18=1+8=9
1+3+1+2+2=9

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Jaydev Dinda   8 years AGO

all numbers in series are divisible by 9.Hence,option3 is answer

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Harijan akhilesh kumar lalchandra   8 years AGO

by adding the digits 9 comes...
5+4=9
2+4+3=9
9+2+7=9 9
3+6+4+5=9 9
so...
1+3+1+2+2=9

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Naresh   8 years AGO

every number exactly divisible by 9.so verification 13122 is correct answer

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Sonu Kumar   8 years AGO

series is 9,54,243,972,3645,?...
sol :-
3^1*3=9
3^2*6=54
3^3*9=243
3^4*12=972
3^5*15=3645
3^6*18=13122
So answer is 3).13122

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Rohit   8 years AGO

3^2×1=9. 3^3×2=54. 3^3×3=243........... 3^7×6=13122(4th one should be 972 not 927 I think pls correct it.)

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JENSI KARUNYA.S   8 years AGO

(3^2)*1=9
(3^3)*2=54
(3^4)*3=243
(3^5)*4=972
(3^6)*5=3645
(3^7)*6=13122
so, option 3) 13122 is the correct answer.

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Ashish Gupta   8 years AGO

0+9=9
5+4=9
2+4+3=9
9+2+7=18; 1+8=9
3+6+4+5=18; 1+8=9
option 3:- 1+3+1+2+2=9

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Sidharth Soren   8 years AGO

3*3^1*1=9
3*3^2*2=54
3*3^3*3=243
3*3^4*4=927
3*3^5*5=3645
3*3^6*6=13122

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cao anh thÆ°   8 years AGO

x=3
x^2,x^3 *2,x^4 * 3,x^5 *4,x^6 *5,x^7 *6
9,54,243,972,3645,13122

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shivam bansal   8 years AGO

sum of digit of first three no.s are 9 and last two are 18 so answer should also have sum of 9 or 18

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aswin das   8 years AGO

given number are divided by 9
so from given option 13122 is divided by 9

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MD AYAZ   8 years AGO

x=3
3*3=9*1=9
3*3*3=27*2=54
3*3*3*3=81*3=243
3*3*3*3*3=243*4=972
3^5=729*5=3645
3^6=2187*6=13122

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sainath   8 years AGO

all numbers in the above sequence are divided by 9 so by trial and error accept 13122 all are not divided by 9 so my opinion is 3

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Mukesh Kumar   8 years AGO

3^2*1=9
3^3*2=54
3^4*3=243
3^5*4=927
3^6*5=3645
3^7*6=13122

Like? Yes (1) | No (2)