If 75 meter wire is used to cover a rectangular plot, then maximum possible area of the plot cove

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03 Mar 2010 max area of plot?

If 75 meter wire is used to cover a rectangular plot, then maximum possible area of
the plot covered by this wire is

OPtion

(1) 1406.25
(2) 312.56
(3) 350.2565
(4) 351.5625
(5) 337.5635
(6) 225.3425
(7) 625
(8) 5025.2225
(9) 25.2255
(10) 525

Solution

The rectangle of maximum area is called square.
Hence we should cover a square plot of side 75/4
Area = (75/4)*(75/4) = 351.5625

Correct Option: 4 Best Solution (5)

HARMEET KAUR   14 years AGO

Perimeter of rectangular plot = 75 M
2*( length +breadth) = 75...length +breadth = 75/2= 37.5 M

Area will be max when rectnagle is having equal sides means the rectangle is a square.
A square is a special kind of rectangle where all four sides have equal length; that is, a square is both a rectangle and a rhombus.

so area of rectangle/ square having max area = (37.5/2)^2 = 18.75^2= 351.5625 sq M

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Dr.Dipin Singh   14 years AGO

Area will be maximum when rectangle is a square having all four sides equal.
If x+y is fixed , then xy is max when x=y.

In this case , x+y = 75/2=37.5

then each side = x=y = 37.5/2= 18.75

Area = 18.75^2 = 351.5625 ... option 4

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Mehul MKDP   14 years AGO

2(18.5+19)= 75
18.5 * 19 = 351.5

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Shikha   14 years AGO

Perimeter of rectangular plot = 75 M
2*( length +breadth) = 75...length +breadth = 75/2= 37.5 M


A square is a special kind of rectangle where all four sides have equal length.
side of rectangle/square for max area = 37.5/2= 18.75 M

so area of rectangle( square) = 18.75^2= 351.5625 sq M

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sujit   14 years AGO

The maximum area :
Actually, the 18.75m X 18.75m square gives the maximum area of any
rectangle of fixed perimeter 75m.

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