Seema bought more mangoes than guavas. She sells mangoes at Rs.23 apiece and makes 15% profit. She s

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06 Jan 2017 Profit

Seema bought more mangoes than guavas. She sells mangoes at Rs.23 apiece and makes 15% profit. She sells guavas at Rs.10 apiece and makes 25% profit. If she gets Rs.653 after selling all the mangoes and guavas, find her profit percentage.

OPtion

1) 15.4%
2) 15.9%
3) 16.4%
4) 16.9%
5) 17.4%
6) 17.9%
7) 18.2%
8) 18.4%
9) 18.6%
10) 18.8%

Solution

Assume Seema Sells X mangoes and Y guavas, where X > Y
Then, 23X + 10Y = 653 ---(i)
Try putting X = 1, 11, 21, 31…
(Why are we trying X =1,11,21? because as per equation (i) last digit of 23*X needs to be3 )
X=1 cannot be true as X>Y
When X=11, Y = 40 so this also cannot be true as X >Y
Next we find X = 21 and Y = 17 is the only solution where X > Y

Cost of aMango = 23/1.15 and cost of aGuava = 10/1.25
Overall cost = 483/1.15 + 170/1.25 = 556
Then profit = 653 – 556=97
Profit percentage = (97/556)×100=17.4%
Option 5)

Correct Option: 5 Best Solution (8)

Mukund Manohar   8 years AGO

SP of 1 Mango = 115% of CP
=> 23 = 115% of CP
CP of 1 Mango = Rs 20
Similarly, CP of 1 Guava = Rs 8
Since,Seema bought more mangoes than guava.
So,By hit & trial method,we get,No. Of mangoes = 21 and No. Of guavas = 17
23*21=483 and 17*10=170
483+170=653,i.e. SP of mangoes and guavas.
Now, CP of mangoes and guavas = (21*20) + (17*8)
= 420+136 = 556
Gain% = (653-556)/100 * 556
= 9700/556
= 17.4%

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madanpal vishwakarma    8 years AGO

CP of mango = (100/(100+15))*23 =20 rs

CP of guava =(100/(100+25))*10 = 8 rs

let she purchase x mangos and y guavas

so
23x +10 y =653

on solving x=21 and y =17
23 x21 + 17 x 10 =653

so total purchase cost
20 x 21 + 8 x 17 = 420 +136 =556

So total profit = 653 -556 =97

So the profit percent is = (97/556)*100 =17.44 %

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Navaneetha Krishnan   8 years AGO

Rs 23 / piece 115 % so cost price is 20 for mangoes
Rs 10 / piece 125% so cost price is 8 for guava
and also by trial and error method i found 21 Mangoes and 17 guava
(21*20) + (17*8) = 556
(21*23) + (17*10)= 653
653-556 = 97
97/556 *100 = 17.44%

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gubba ranjith kumar   8 years AGO

actual mango cost =20
Total mangoes cost=20×21=420
actual guava cost=8
Total guava cost=8×17=136
Total=420+136=556
Profit=(653-556)/556×100=17.4

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Sujata   8 years AGO

here,
Let number of mangoes be x and guavas be y,
so according to question,
23x+ 10y =653......i
now, we can find CP of each mango and Guava as 20 and 8.
Now from the equation, and question, number of mangoes are found to be 21,
as, 23*21=483, so 653-483=170, i.e divisible by 10,
Thus total number of mangoes and guavas are 21 and 17. So, total cost price is now, 20*21+8*17=556,
so total profit is, 17.44%

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veera babu   8 years AGO

(21×23)+(10×17)=653
profit=483*15/100+170×25/100=114.95
gain%=114.95*100/653=17.4

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SORNA KAMALAM S   8 years AGO

s.p profit c.p
23 15 20
10 25 10

23m+10g=653
m>g
using trial and error, m=21,g=17

c.p s.p profit
(420+136=556) (483+170=653) 17.4

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Pabitra Paul   8 years AGO

c.p of mango = (100/115)*23=Rs.20
and for guea it will be =(100/125)*10=8
now assume that there are 21 mangos and 17 guea
then the total ost prie will be=(21*20)+(17*8)=556
so total profit will be =(( (653-556)/556))*100=17.4(ans)

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