What is the 9th term of below series? 6, 15, 35, 77, 143, .....

Baishali Roy   7 years AGO

6,15,35,77,143,___,___,___,___.
Now,
6=2*3
15=3*5 (1st number to be multiplied is 2nd multiplied digit of previous number and the 2nd number to be multiplied is a prime number)
35=5*7
77=7*11
143=11*13
Then,
6th no=13*17
7th no=17*19
8th no=19*23
9th no=23*29=667 (Opt. 9) (Ans).

Like? Yes (9) | No (2)  

div   7 years AGO

product of prime no. sequence
6->2*3
15->3*5
35->5*7
.
.
23*29->667

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Dr.Dipin Singh   7 years AGO

multiplication of 9th and 10 th prime number
i.e. 23*29=667

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MP    7 years AGO

29x23=667
product of consecutive prime numbers.

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VIKAS BAIRWAL   7 years AGO

it follows the series of (3*2, 5*3, 7*5, 11*7, 13*11,........and so on.) so according to this series the 9th digit will be (29*23) that is equal to 667

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vemula haritha   7 years AGO

6=2x3,15=3x5,35=5x7,.....continues i.e product of consecutive prime numbers so product of 23x29=667 which is the 9th term

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srivatsan   7 years AGO

3*2=6
3*5=15
5*7=35
11*7=77
11*13=143
13*17=221
17*19=323
19*23=437
23*29=667 the product of two consecutive prime numbers is the concept used here .
The ninth term is 667

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sanju   7 years AGO

Product of Consecutive Prime Numbers
2*3=6
3*5=15
5*7=35
7*11=77
11*13=143

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Aakash kesarwani   7 years AGO

In the series each number is the product of its consecutive prime no. as given below,
2*3=6
3*5=15
5*7=35
7*11=77
11*13=143
13*17=221
17*19=323
19*23=437
23*29=664 which is the 9th term in the series. Answer

Like? Yes | No (1)  

THOTA VIJAYA   7 years AGO

2X3 =6
3X5 =15
5X7=35
7X11=77
11X13=143
13X17
17X19
19X23
23X29=667

Like? Yes | No (1)  

Neeraj   7 years AGO

this series is the product of two consecutive prime number
prime number are 2 3 5 7 11 13 17 19 23 29
2*3=6
3*5=15
5*7=35
7*11=77
11*13=143
13*17=221
17*19=323
19*23=437
23*29=667

Like? Yes | No (1)  

Ansh   7 years AGO

The given series is of the form = 2*3, 3*5, 5*7, 7*11---------
as we see tha every no. in the series is the producct of two consecutive prime no's hence if we go over them we get the ninth term as (23*29) which is eq. to 667

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DHANANJAY KUMAR   7 years AGO

In this series is a multiplication of two consecutive prime number from starting
prime numbers are 2,3,5,7,11,13,17,19,23,29....
Here, 2*3=6
3*5=15
5*7=35
7*11=77
11*13=143
13*17=196
17*19=323
19*23=437
23*29=667
so ans is 667 and option is (9)

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Saraswat Rit   7 years AGO

3*2=6
5*3=15
7*5=35
11*7=77
13*11=143
similarly 29*23=667

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Rakesh   7 years AGO

2*3=6
3*5=15
5*7=35
7*11=77
11*13=143
like these are prime numbers
so 9th term is 23*29=667
so opt is 9

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DIVYANSHU SHEKHAR   7 years AGO

2*3=6
3*5=15
5*7=35
7*11=77
........
23*29=667

Like? Yes | No (2)  

Anandita Rani   7 years AGO

6 = 2*3
15 = 3 * 5
35 = 5 * 7
77 = 7 * 11
143 = 11 * 13
221 = 13 * 17
323 = 17 * 19
437 = 19 * 23
667 = 23 * 29

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Dharmendra kumar   7 years AGO

divide next term by previous term....
you got the pattern....

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Chinmay Swarup Chiranjeevi   7 years AGO

product of consecutive prime numbers starting from 2,3,5,7....

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RAJ   7 years AGO

2*3=6,
3*5=15
5*7=35
.
.
.
.
.
.
.
.
23*29=667(Answer)

Like? Yes | No (2)  

SORNA KAMALAM S   7 years AGO

2*3=6
3*5=15
5*7=35
7*11=77
11*13=143
13*17=221
17*19=323
19*23=437
23*29=667

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Pragati Rode   7 years AGO

Series having the pattern that product of prime number

First element = 2*3 = 6
second element = 3*5 = 15
Third element = 5*7 = 35
Fourth element =7*11= 77
Five element =11*13 = 143
six element =13*17 = 221
Seventh element =17*19= 323
Eighth element =19*23 = 437
Nineth element =23*29 = 667
so option is 9

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arvind rathod   7 years AGO

2*3=6
3*5=15
5*7=35
7*11=77
11*13=143
13*17=221
17*19=323
19*23=437
23*29=667
These r the consecutive prime numbers
Hence 9th number is 667

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Bhushan   7 years AGO

Multiply prime numbers
2*3, 3*5, 5*7 , 7*11, 11*13 and so on 9th term is 23 * 29

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sachidanand yadav   7 years AGO

6=2 * 3
15=3 * 5
35=5 * 7
77=7 *11
143=11*13
221=13*17
323=17*19
437=19*23
667=23*29

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sruthi pujari   7 years AGO

Product of successive primes 2*3;3*5 in this way 9th term is 23*29 =667

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shraboni   7 years AGO

2×3=6
3×5=15
5×7=35
7×11=77
11×13=143
13×17=221
in this order if we continue then at the 9th term we get 23×29 which is equals to 667
and the no we multiply each time must be a odd one
so I multiply 3 ,5, 7 ,11 ,13 ,17, 19 ,23 ,29

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SATHEESH V   7 years AGO

2*3 , 3*5 , 5*7 , 7*11 , 11*13 , 13*17 , 17*19 , 19*23 , 23*27,...............
23*27=667

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MOHAMMED JAFFAR   7 years AGO

Product of consecutive prime numbers...

1st term 2x3 = 6
2nd term 3x5 = 15
3rd term 5x7 = 35
4th term 7x11 = 77
5th term 11x13 = 143
6th term 13x17 = 221
7th term 17x19 = 323
8th term 19x23 = 437
9th term 23x29 = 667

Option (9)

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Sunil kumar   7 years AGO

multiple of two prime no.
2*3=6
3*5=15
5*7=35
......
..
..
23*29=667

Like? Yes | No (3)