Two ships are sailing in the sea on the two sides of a lighthouse. The angle of elevation of the top of the lighthouse is observed from the ships are 30° and 45° respectively. If the lighthouse is 169 m high, the distance between the two ships is:
OPtion
1) 460.72 m
2) 468.72 m
3) 463.72 m
4) 464.72 m
5) 461.72 m
6) 465.72 m
7) 467.72 m
8) 469.72 m
9) 462.72 m
10)None of these
Solution
Let AB be the lighthouse where A is the bottom point of light house and C and D be the positions of the ships.
Then, AB = 169 m, Angle ACB = 30° and angle ADB = 45°.
AB/AC = tan 30° = 1/sq root(3)
=> AC = AB * sq root(3) = 169*3^(1/2)