A sum fetched a total simple interest of Rs. 63 at the rate of 5% p.a. in 3 years. What is the sum?

AYAN PAUL   7 years AGO

We know the formula for Simple Interest is (P*T*R)/100
Where P = Principal T = Time & R = Rate of interest
now putting these values from the question we can write
P = 63*100/3*5 = Rs. 420

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PRABHAT KUMAR   7 years AGO

63=(P*5*4)/100
therefore P=420
option 3
chess

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G.S.Kantharao   7 years AGO

P=100I/TR=100*63/3*5=2100/5=₹420
Hence my option is 3👈.

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Maddi raju   7 years AGO

I=PTR/100
I=63,T=3,R=5
substitute the above values in above equation,we get P=420

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Anupam Tripathi   7 years AGO

We know that SI=(P*R*T)/100
R=5%, T=3 Years, SI=63
Then,
63=(P*5*3)/100
6300=PI*15
6300/15=PI
420=PI
Here PI is the sum.
So total sum=420

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Samiksha Sonam   7 years AGO

SI=63
Rate=5%
Time=3 years
SI=P*R*T/100
P=420

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somen sarkar   7 years AGO

S.I.=prt/100
where S.I.=63, r=5%, t=3, p=?

p=63*100/(3*5)=420

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atheesh padala   7 years AGO

I=PTR/100
P=(100I)/(TR)
P=(100*63)/(3*5)=420/-

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shraboni   7 years AGO

let sum is P
S.I=P*T*R/100
(P*3*5)/100=63
or, P =420

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Auditya   7 years AGO

I=ptr/100
Given I =63, t=3,r=5
P=((100*I)/(t*r))
=((100*63)/(3*5))
=420

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Surbhi   7 years AGO

simple interest = (P*R*T)/100
63 = (x*5*3)/100
x =420

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Praveenkumar P Kalikeri   7 years AGO

Simple Interest = ( Principal *Time *Rate of Interest) /100
Therefore, Principal = [( Simple Interest *100)/ ( Time * Rate of Interest)]

P= [(63*100)/(3*5)] = 20*21 = Rs. 420

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Divya Batra   7 years AGO

solution is apply the formula of simple interest.
63=(P*5*3)/100
therefore, P=(63*100)/15=420

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Priyanka   7 years AGO

s.i=63
sum or principal (p)=?
t=3
r=5
s.i= p*t*r/100
63=p*5*3/100
p=420

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Shaswata Bisi   7 years AGO

SI=P*R*T/100
63=P*5*3/100
P=6300/15
P=420

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raksha s shetty   7 years AGO

simple interest=Principle*time*rate of interest/100
the sum is =principle=S.I*100/(TIME*R)=420

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thirunavukarasu raja   7 years AGO

si=pnr/100 using that formula
63=p*3*5/100
p=63*100/3*5
p=420

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Akshata   7 years AGO

(P×(R+5)×3/100 )-(P×R×3/100)=63
(3PR+15P-3PR)=6300
P=6300/15
P=420

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Renu   7 years AGO

Let sum=A,
A*5/100*3=63
A*0.15=63
A=63/0.15
A=420

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Bodla Anupriya   7 years AGO

simple interest=sum*rate*no. of years/100
63=sum*5*3/100
by solving we get sum= 420rs
ans is option 3

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Ezhil Kumar.P   7 years AGO

simple interest =P*R/100*T
63=P*5/100*3
Solving,P=420

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mukesh   7 years AGO

this is an easy method on the topic of simple interest.
the answer is 420.
the formula for this question is ,SIMPLE INTEREST =P*R/100*T,
Here SI=63,R=5,T=3,P=?.Use the formula and you will get the answer 420.

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Raji Baskar   7 years AGO

S.I= P*T*R/100
63=P*3*5/100
Solving We Get,
P=Rs420

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rahul   7 years AGO

for 1 year 5%,for 3 years it will be 15% for 420 rs simple interest is 63

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DEBOJYOTI CHAKRABORTY   7 years AGO

sum=(interest*100)/(rate*time)
sum=420

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Moni Shankar   7 years AGO

s.i=Rs.63,n=3,r=5%;

p=s.i*100/(n*r)
p=(63*100)/(5*3)
p=Rs.420

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sanjoli   7 years AGO

SI =p*r*t/100

SI=63 , r=5 , t=3
p= (SI * 100)/(r*t)
On substitution we get
p=420

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Sisindra   7 years AGO

Simple interest=ptr/100
P=principal amount
T=time period
R=Rate of interest per annum
So P=6300/15 =420

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mohit   7 years AGO

5% of 420 = 21
for 3 years 21*3 = 63 is the interest fetched

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MOHIT KUMAR   7 years AGO

because one year interest of 420 is 21
then 3 year interest of 420 is=21*3=63

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8880866556   7 years AGO

63 is the simple interest for 3 year
calculate for one year it will be 63/3 = 21
For one year 21 rps interest as 5%
So for 100% how much 100/5 = 20
than 21*20 = 420

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Akash Gupta   7 years AGO

interest=p*t*r/100

therefore, p=i*100/(r*t)
p=(63*100)/(5*3)
=420

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kanimozhi kalimuthu   7 years AGO

simple interest=(sum*rate*yrs)/100
sum=(63*100)/(5*3)=rs.420

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