M4maths Previous Puzzles

02 Apr 2010 3 Distinct Number

There are 3 distinct numbers whose sum and product are equal. The sum of cubes of the three numbers is

OPtion

1) 12
2) 28
3) 15
4) 36
5) 20
6) 54
7) 37
8) 52
9) 78
10) 64

Solution

These 3 numbers are 1, 2 & 3
Sum of their cubes is 1 + 8 + 27 = 36

Correct Option: 4 Best Solution (14)

Dr.Dipin Singh   15 years AGO

x+y+z= xyz, then x=1,y=2,z=3 so that 6=6, then


x^3+y^3+z^3= 1+8+27=36... option 4

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Saranjit Singh   15 years AGO

1x2x3=6
1+2+3=6
1^3+2^3+3^3
=1+8+27=36 the answer

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HARMEET KAUR   15 years AGO

1^3+2^3+3^3=36
no.4 is correct

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sanjib biswas   15 years AGO

the three distinct no is 1,2,3 then 1^3+2^3+3^3=36

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sujit   15 years AGO

1 , 2, 3

1+2+3=6
1*2*3=6
1^3 + 2^3 + 3^3 = 1+8+27 = 36

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kewal   15 years AGO

1+2+3=1*2*3=6

Now 1+8+27=36

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Jeevan   15 years AGO

1+8+27=36

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shailender   15 years AGO

1+2+3=1*2*3
1^3+2^3+3^3=36

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Abhishek Mukherjee   15 years AGO

three distinct nos. are 1,2 and 3.sum is 6 which is also the prod. hence,sum of cube of 3 nos.is36

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Mehul MKDP   15 years AGO

1 2 3

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neena   15 years AGO

3+2+1=3*2*1
3^3+2^3+2^3
=36

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sivakumar   15 years AGO

1+2+3 = 1*2*3
cube of 1 (1)+ cube of 2 (8)+ cube of 3 (27)= 36

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Achelal Sharma   15 years AGO

1,2,3 so the sum of the cubes are 36

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Angarayan Sundarakalatharan   15 years AGO

1,2,3. 1+8+27=36

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