M4maths Previous Puzzles

02 Apr 2010 3 Distinct Number

There are 3 distinct numbers whose sum and product are equal. The sum of cubes of the three numbers is

OPtion

1) 12
2) 28
3) 15
4) 36
5) 20
6) 54
7) 37
8) 52
9) 78
10) 64

Solution

These 3 numbers are 1, 2 & 3
Sum of their cubes is 1 + 8 + 27 = 36

Correct Option: 4 Best Solution (14)

Dr.Dipin Singh   14 years AGO

x+y+z= xyz, then x=1,y=2,z=3 so that 6=6, then


x^3+y^3+z^3= 1+8+27=36... option 4

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Saranjit Singh   14 years AGO

1x2x3=6
1+2+3=6
1^3+2^3+3^3
=1+8+27=36 the answer

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HARMEET KAUR   14 years AGO

1^3+2^3+3^3=36
no.4 is correct

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sanjib biswas   14 years AGO

the three distinct no is 1,2,3 then 1^3+2^3+3^3=36

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sujit   14 years AGO

1 , 2, 3

1+2+3=6
1*2*3=6
1^3 + 2^3 + 3^3 = 1+8+27 = 36

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kewal   14 years AGO

1+2+3=1*2*3=6

Now 1+8+27=36

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Jeevan   14 years AGO

1+8+27=36

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shailender   14 years AGO

1+2+3=1*2*3
1^3+2^3+3^3=36

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Abhishek Mukherjee   14 years AGO

three distinct nos. are 1,2 and 3.sum is 6 which is also the prod. hence,sum of cube of 3 nos.is36

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Mehul MKDP   14 years AGO

1 2 3

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neena   14 years AGO

3+2+1=3*2*1
3^3+2^3+2^3
=36

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sivakumar   14 years AGO

1+2+3 = 1*2*3
cube of 1 (1)+ cube of 2 (8)+ cube of 3 (27)= 36

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Achelal Sharma   14 years AGO

1,2,3 so the sum of the cubes are 36

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Angarayan Sundarakalatharan   14 years AGO

1,2,3. 1+8+27=36

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