Divide Rs. 16653 into 3 parts so that their amount after 2,3 and 4 years respectively may be equal,

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04 Jul 2018 Simple Interest

Divide Rs. 16653 into 3 parts so that their amount after 2,3 and 4 years respectively may be equal, the rate of interest being 5% per annum at simple interest. The second part is

OPtion

1) 5313
2) 5544
3) 5796
4) 5323
5) 5539
6) 5791
7) 5315
8) 5545
9) 5792
10) None of these

Solution

Let the parts be x, y and z
x + (x * 2 * 5/100) = y + (y * 3 * 5/100) = z + (z * 4 * 5/100)
11x/10 = 23y/20 = 6z/5 = k
x = 10k/11, y = 20k/23, z = 5k/6
But x + y + z = 16653
10k/11 + 20k/23 + 5k/6 = 16653
k = 6375.6
y = (20/23)*6375.6 = 5544
Hence, the second part is Rs. 5544

Correct Option: 2 Best Solution (4)

Dr.Dipin Singh   6 years AGO

If x is the amount after 2,3 and 4 years of each part, then
x/1.1 +x/1.15 +x/1.3= 16653
Then x= 6375.6 Rs
Second part = 6375.6/1.15 = Rs 5544

Like? Yes (5) | No (5)  

G.S.Kantharao   6 years AGO

Let x,y,z are amounts
[x+(x*2*5/100)]=[y+(y*3*5/100)]=[z+(z*4*5/100)]
110x=115y=120z
x/y=23/22
y/z=24/23
x:y:z=276:264:253
y =₹16653*264/793=₹5544
Hence my option is 2👈

Like? Yes (4) | No (5)  

Advithi   6 years AGO

LET x,y,z be the parts
x+intrest on x for 2 years=y+intrest on y for 3 years=z+intrest on z for 4 years
x+x/10=y+3y/20=z+z/2
22x=23y=24z
x+y+z=16653
sustituting we get y= 5544

Like? Yes (1) | No (5)  

Kariamal   6 years AGO

x+(x*5*2/100)=y+(y*5*3/100)=z+(z*5*4/100)
11x/10=23y/20=6z/5=k
So x+y+z=16653
k=6375.6
y=20/23*6375.6
y=5544

Like? Yes | No (6)