M4maths Previous Puzzles

03 Jan 2018 Probability

What is the probability of getting a product of 12 from three throws of a dice?

OPtion

1) 8/216
2) 6/216
3) 10/216
4) 12/216
5) 15/216
6) 16/216
7) 1/26
8) 1/24
9) 1/27
10)None of these

Solution

Total Number of possible outcomes = 6C1*6C1*6C1 = 6*6*6 = 216
Positive outcomes must satisfy D1*D2*D3= 12
Below are such values of D1, D2 and D3:
1, 6, 2
1, 4, 3
1, 3, 4
1, 2, 6
2, 6, 1
2, 3, 2
2, 2, 3
2, 1, 6
3, 4, 1
3, 2, 2
3, 1, 4
4, 3, 1
4, 1, 3
6, 2, 1
6, 1, 2

Count of positive outcome = 15
Probability = Positive outcome/Total Possible Outcomes = 15/216
Option 5)

Correct Option: 5 Best Solution (0)