Number of methods of arranging 4 boys and 4 girls in a round table such that no 2 girls sit togeth

M4maths Previous Puzzles

30 Apr 2010 NO two girl sit together

Number of methods of arranging 4 boys and 4 girls in a round table such that no 2 girls sit together is ?

OPtion

1) 36
2) 576
3) 72
4) 40320
5) 144
6) 24
7) 6
8) 5040
9) 8
10) 4

Solution

Method- First we have to arrange 4 boys after than 4 girls according to the given condition
Number of methods of arranging 4 boys in a round table is 3*2*1 = 6
Number of methods of arranging 4 girls between boys is 4*3*2*1 = 24
Hence total no. of methods is 6*24 = 144

Correct Option: 5 Best Solution (4)

SUDESHNA SEN   14 years AGO

4 boys can sit in a round table in (4-1)!= 3!= 6 ways.
Now there are 4 spaces in between the 4 boys. If no 2 girls sit together then the 4 girls have to sit in these 4 black spaces, which can be done in 4!= 24 ways.
Therefore, total number of methods of arranging 4 boys and 4 girls in a round table such that no 2 girls sit together is= 6*24= 144.....Option 5)

Like? Yes (3) | No   

S. Singh   14 years AGO

3!*4!= 6*24=144

Like? Yes (1) | No   

ASHOK ROY   14 years AGO

4 boys can sit in a round table in (4-1)!= 3!= 6 ways.
Now there are 4 spaces in between the 4 boys. the 4 girls have to sit in these 4 places as no 2 girls can sit together.
No. of methods to place the 4 girls in these 4 places= 4!= 24
Therefore, total number of methods of arranging 4 boys and 4 girls in a round table such that no 2 girls sit together is= 6*24= 144.....Option 5)

Like? Yes (1) | No   

RASHI   14 years AGO

3!*4!

Like? Yes (1) | No (1)