A merchant has 550 kg of sugar, part of which he sells at 4% loss and the rest at 6% profit. He gain

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06 Jun 2018 Mixture

A merchant has 550 kg of sugar, part of which he sells at 4% loss and the rest at 6% profit. He gains 2% on the whole. What is the difference between the quantities of sugar sold at 6% profit and that sold at 4% loss?

OPtion

1) 93 kgs
2) 120 kgs
3) 105 kgs
4) 115 kgs
5) 125 kgs
6) 130 kgs
7) 135 kgs
8) 110 kgs
9) 220 kgs
10)None of these

Solution

(Quantity of Cheaper)/(Quantity of Dearer) = (Price of Dearer - Mean Price)/(Mean Price - Price of Cheaper)

(Quantity of Cheaper)/(Quantity of Dearer) = (106 - 102)/(102-96) = 4/6 = 2/3

Total Quantity = 550 KG

The quantity sold at 4% loss is = (2/5) * 550 = 220 Kgs
The quantity sold at 6% profit is = (3/5) * 550 = 330 Kgs
Difference between Quantity = 330-220 = 110 Kgs


Option 8)

Correct Option: 8 Best Solution (5)

ruby   6 years AGO

We can use Alligation and Mixture concept to solve this problem.
-4(loss) 6(gain)

2(overall gain)
6-2=4 2-(-4)=6

Ratio = 4:6=>2:3
Difference in quantities 550/5*1=110

or

Quantity sold at 4%loss = 550/5*2=220
Quantity sold at 6% gain = 550/5*3 = 330
So difference =110
hence option 8

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Titir Misra   6 years AGO

Applying the rule of mixture, we get the ratio to be 2:3
thus the weights are 220 kg an d 330 kg. diff between the weights is 110 kg

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Varun   6 years AGO

Let x be the quantity sold at loss, i.e. at 4%
=> -4x/100....(1)
Then 550-x is sold at 6% profit
=> (550-x)×(6/100).....(2)

Gains 2% profit on 550 = (2/100)×550....(3)

(1)+(2) = (3)

Simplifying, x = 220
So 500-220 = 330

And the difference is 330-220 = 110

= Option (8)

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SAYAN CHATTERJEE   6 years AGO

(96Cx/100+(550-x)*106/100-550C)/550C= 2/100.
x= 220 ( 4% loss) and so, rest is (550-220)= 330 ( 6% profit).
So, the difference is (330-220) = 110.
Option 8.

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G.S.Kantharao   6 years AGO

Quantity of cheaper/Quantity of Dearer=(106-102)/(102--96)=4/6=2/3
Quantity of loss=550×2/5=220
Gain=330
Difference=110kg
My option is 8👈

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