M4maths Previous Puzzles

11 Sep 2019 Age

The present ages of A,B and C are in proportions 2:4:7. Four years ago, the sum of their ages was 66. What is the product of their present ages?

OPtion

1) 7500
2) 12960
3) 3840
4) 12096
5) 30720
6) 24000
7) 43740
8) 42000
9) 19440
10) None of these

Solution

Answer: 12096 years


Four years ago sum of Ages of A, B and C = 66
Four years later i.e. sum of current ages of A, B and C = 66 + 3*4 = 78

Present Age of A = 78*2/(2+4+7) = 12 years

Present Age of B = 78*4/(2+4+7) = 24 years
Present Age of C = 78*7/(2+4+7) = 42 years

Product of their ages = 12096

Option 4)

Correct Option: 4 Best Solution (5)

Elizabeth Pothen   5 years AGO

Let present ages be 2x, 4x and 7x
4 years ago,
2x -4 +4x-4+7x-4= 66
Solving x = 6
So 2*6*4*6*7*6 = 12096

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SAYAN CHATTERJEE   5 years AGO

2x+4x+7x-12= 66
x= 6
So, product of present age is 2*4*7*36= 12096.
Option 4.

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Vivek Choudhary   5 years AGO

A:B:C
2:4:7
four years ago age was be = 66
so now, 66+12(4*3)=78
so, A's age = 2*78/13=12
B= 24,C = 42
product= 12096

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Varun   5 years AGO

Let the present ages be 2x,4x,7x
Then there ages before 4 years
= 2x-4 , 4x-4, 7x-4
And this sums upto 66
=>x=6
So present ages are 12 24 42
And product = 12096
= Option (4)

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RAMADURAI NATESAN   5 years AGO

Let present ages be 2x,4x and 7x.
Sum of ages 4 years ago will be 13x - 12 = 66. x = 6.
present ages are 12, 24 and 42. Product is = 12096.

Like? Yes | No