Run Scored by Murali, Shikhar, Rahul, Virat, Ajinkya, Hardik, Dinesh, Ashwin, Shami, Ishant and Ume

M4maths Previous Puzzles

30 Aug 2018 Statistics

Run Scored by Murali, Shikhar, Rahul, Virat, Ajinkya, Hardik, Dinesh, Ashwin, Shami, Ishant and Umesh in 1st Match are:
33 24 19 21 41 39 37 47 38 29 and 26 respectively.

Run Scored by Murali, Shikhar, Rahul, Virat, Ajinkya, Hardik, Dinesh, Ashwin, Shami, Ishant and Umesh in 2nd Match are:
13 44 19 93 41 76 33 44 29 11 and 7 respectively



What is the difference between population standard deviation between second match and first match?

OPtion

1) 25.807
2) 18.791
3) 17.589
4) 16.981
5) 18.183
6) 17.197
7) 16.817
8) 17.961
9) 8.610
10)None of these

Solution

1st Match
Mean of 11 scores = 354/11 = 32.18
Sum of squared difference from mean for each number = (33-32.18)^2 + (24-32.18)^2 + ......+ (26-32.18)^2 = 815.6364

Average of Squared difference (Variance) = 815.6364/11 = 74.1487
Population Standard Deviation = Square root of variance = 74.1487^1/2 = ~8.610


2ns Match
Mean of 11 scores = 410/11 = 37.27273
Sum of squared difference from mean for each number = (13-37.27)^2 + (44-37.27)^2 + ......+ (7-37.27)^2 = 7326.18

Average of Squared difference (Variance) = 7326.18/11 = 666.016
Population Standard Deviation = Square root of variance = 666.016^1/2 = ~25.807

Difference between Population standard deviation of 2nd match and 1st match = 25.807 - 8.610 = ~17.197

Option 6)

Correct Option: 6 Best Solution (3)

Shanjay Sundar . D   6 years AGO

sq rt(1109.81-1035.55)
=8.61
sq rt(2055.27-1389.25)
=25.80
25.80-8.61=17.197

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vaishali more   6 years AGO

.

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Irfana fathima   6 years AGO

Standard deviation follows the below rule
Find AVG of the runs scored
Subtract AVG from the scores
Find square of the above subtracted scores and take AVG of that
Take square root of the AVG we obtain the Standard Deviation
Match 1 standard deviation 8.610967
Match 2 Standard deviation 25.8074
We get, 17.19645
Approximately the answer will be 17.197

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