Find the value of 2x^2 + 4zy + 3z^2 where x = Mean , y = Median and z = Mode of following numbers:

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27 Nov 2018 Find Value of

Find the value of 2x^2 + 4zy + 3z^2
where x = Mean , y = Median and z = Mode of following numbers:
77 104 91 97
131 48 114
119 91 117 122

OPtion

1) 83701
2) 87261
3) 81261
4) 89261
5) 83261
6) 83101
7) 81101
8) 88101
9) 86261
10) None of these

Solution

Mean x = Sum of nos. / Count of numbers = 1111/11 = 101
Median y = Middle term when number are arranged in ascending order = 104
Mode z = Number which is present maximum number of times = 91
2x^2 + 4zy + 3z^2 = 2* (101)^2 + 4*91*104 + 3*(91)^2 = 83101

Option 6)

Correct Option: 6 Best Solution (1)