A is 20 years older than B who is five times as old as C. The total of the ages of A, B and C is 174

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27 Oct 2020 Age

A is 20 years older than B who is five times as old as C. The total of the ages of A, B and C is 174 years. What is the value when the square of age of B is multiplied to the sum of ages of A and C ?

OPtion

1) 582500
2) 563500
3) 542500
4) 533500
5) 509600
6) 552550
7) 560500
8) 532500
9) 586500
10)None of these

Solution

Let’s assume Age of B be B years
Age of A = B+20
Age of C = B/5

Total age = B + 20 + B + B/5 = 174
Solving 11B/5 = 154
B = 70
A = 70+20 = 90
C = B/5 = 14

Final Value = (Age of B)^2 * (Age of A + Age of C) = 70^2 * (104) = 509600

Option 5)

Correct Option: 5 Best Solution (0)