A mixture contains 3 components A, B and C in the ratio 3:4:5. If difference of the amount of B an

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25 May 2010 Mixture Of 3 component

A mixture contains 3 components A, B and C in the ratio 3:4:5. If difference of the amount of B and C is 19 Kg,
then total mass of the mixture is

OPtion

1) 189
2) 230
3) 224
4) 220
5) 210
6) 228
7) 168
8) 320
9) 290
10) 300

Solution

Let the amounts of A, B and C are 3x, 4x and 5x respectively, then according to the given condition 5x – 4x = 19

Hence x = 19

Total amount of the mixture = 12 x = 12*19 = 228

Correct Option: 6 Best Solution (18)

Dr.Dipin Singh   14 years AGO

if x kg is total mixture , then
x*1/12= 19 or x=228 kg

Like? Yes (1) | No   

Karthik Pandiyan   14 years AGO

Let the B's mass be 4x and c's mass be 5x
Diff b/w B and C =19>>> 5x-4x=19
x=19
Sub valve in the ratio we get (3*19)+(4*19)+(5*19)=228

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~Sandeep~   14 years AGO

(5/12 -4/12)x = 19 => x=228

Like? Yes (1) | No   

Deepak Upreti   14 years AGO

let amount of mixture A, B, C are x, then 5x-4x=19
so x=19
so the total mixture is 12*19=228

Like? Yes (1) | No   

Saswata Chakraborty   14 years AGO

5x-4x=x=19kg
total mass=12x=228kg

Like? Yes (1) | No   

SUDESHNA SEN   14 years AGO

Let A, B and C be 3x, 4x and 5x respectively.
Then as per given condition, 5x-4x= 19 kg, or, x= 19 kg.
Therefore, total mass of the mixture= 3x+4x+5x= 12x= 12*19 kg= 228 kg.....Option 6)

Like? Yes (1) | No   

Karan   14 years AGO

12*19=228

Like? Yes (1) | No   

ASHOK ROY   14 years AGO

Let A, B and C be 3x, 4x and 5x respectively.
Then as per given condition, 5x-4x= 19 kg, or, x= 19 kg.
Therefore, total mass of the mixture= 3x+4x+5x= 12x= 12*19 kg= 228 kg.....Option 6)

Like? Yes (1) | No   

Mamon Sengupta   14 years AGO

Let A, B and C be 3x, 4x and 5x respectively.
Then as per given condition, 5x-4x= 19 kg, or, x= 19 kg.
Therefore, total mass of the mixture= 3x+4x+5x= 12x= 12*19 kg= 228 kg.....Option 6)

Like? Yes (1) | No   

Trishita Dasgupta   14 years AGO

Let A, B and C be 3x, 4x and 5x respectively.
Then as per given condition, 5x-4x= 19 kg, or, x= 19 kg.
Therefore, total mass of the mixture= 3x+4x+5x= 12x= 12*19 kg= 228 kg.....Option 6)

Like? Yes (1) | No   

sanjib biswas   14 years AGO

difference of mixer B&C is 19 i.e. 5-4=1 then total mass mixer is (3+4+5)*19=228

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Prabir Sen   14 years AGO

total mass mixer is (3+4+5)*19=228

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sivakumar   14 years AGO

A:B:C = 3:4:5; SINCE C IS HIGHER THAN B , C-B = 19 --- EQUATION (1) ;C=5/4*B; SUBSTITUTE IN
EQUATION (1) AND SOLVE; B=76; SUBSTITUTE IN EQUATION (1); C=95; A=57; A+B+C=228;

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susmit   14 years AGO

DIFFERENCE BETWEEN B AND C IS 19 SO B IS 19*4=76 AND C IS 19*5= 95 AND A IS 19*3= 57 SO TOTAL IS 228

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Khanna   14 years AGO

19*12/1= 228 kg

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Jagat   14 years AGO

12*19=228

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kewal   14 years AGO

A mixture contains 3 components A, B and C in the ratio 3:4:5 . say 3x, 4x and 5x respectively.

Then total mixture is 12 x where x= difference of 5x and 4x= 19 kg.

Then total mixture = 12x=12*19=228 kg

Like? Yes (1) | No   

Mihir   14 years AGO

If diff is 1 kg, then total wt=12 kg

If diff is 19 kg, then total wt=12*19=228 kg

Like? Yes (1) | No