A mixture contains sugar solution and colored water in the ratio 3 : 5. If 16 liters of colored wate

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27 Dec 2018 Mixture

A mixture contains sugar solution and colored water in the ratio 3 : 5. If 16 liters of colored water is added to the mixture, the ratio becomes 4 : 7. Find the initial quantity of colored water in the given mixture (in liters).

OPtion

1) 192
2) 120
3) 240
4) 160
5) 180
6) 320
7) 360
8) 150
9) 200
10) None of these

Solution

The initial ratio is 3 : 5
Let ‘k’ be the common ratio.
=> Initial quantity of sugar solution = 3 k
=> Initial quantity of colored water = 5 k
=> Final quantity of sugar solution = 3 k
=> Final quantity of colored water = 5 k + 16

Final ratio = 3 k : 5 k + 16 = 4 : 7
=> 21 k = 20k + 64
=> k = 64
Therefore, initial quantity of colored water in the given mixture (in liters) = 5 * 64 = 320 liter

Correct Option: 6 Best Solution (6)

G.S.Kantharao   5 years AGO

Let Sugar solution : Coloured water =x : y
X:Y=3:5=>5x=3y=> x=3y/5
X:(Y+16)=4:7=>7x=4y+64
7(3y/5)=4y+64
0.2y=64=>y=320
My option is 6👈

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Kariamal   5 years AGO

3x/5x+16=4/7
x=64
Initial quantity 5x=320

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SAYAN CHATTERJEE   5 years AGO

3x/(5x+16)= 4/7
So, x= 64
So, colored water is 64*5= 320.
Option 6.

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RAMADURAI NATESAN   5 years AGO

Let initial mixture be 3x sugar and 5x col.water.After adding 16 l col.water,the mixture will be 3x sugar and 5x+16 col water.3x : (5x+16) :: 4:7 . 21x =4(5x+16) . x= 64.
Initial quantity of col water = 5x = 5*64 =320

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Soniya Chhatri   5 years AGO

3x/5x+16=4x/7x
X=64
5x=320

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Veluprabhakaran.K   5 years AGO

x/y=3/5,x/(y+16)=4/7
5x-3y=0
7x-4y=64
x=192
y=320

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