Length, breadth and height of a room are 20 feet, 15 feet and 10 feet respectively. Maximum length

M4maths Previous Puzzles

28 May 2010 Rod in room?

Length, breadth and height of a room are 20 feet, 15 feet and 10 feet respectively. Maximum length (in integer)
of a rod placed in the room is

OPtion

1) 32
2) 25
3) 24
4) 27
5) 28
6) 29
7) 30
8) 31
9) 26
10) 23

Solution

Diagonal is the greatest length inside the room, its value = (20^2+15^2+10^2)^1/2 = (725)^1/2
= 26.926 = 26 in integer form

Correct Option: 9 Best Solution (8)

Deepak Upreti   14 years AGO

since the diagonal is the greatest length of any cubic object, so that D=(20^2+15^2+10^2)^1/2=(725)^1/2=26.9
hence the appropriate length of rod is 26A

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Dr.Dipin Singh   14 years AGO

Length, breadth and height of a room are 20 feet, 15 feet and 10 feet respectively.
so
Maximum length of a rod placed in the room =
Sq root [ 20^2+15^2+10^2) = root 725 =26.925 ft

so max integer length =26 ft

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HARMEET KAUR   14 years AGO

Maximum length (in integer)
of a rod placed in the room is
Sq root [ 20^2+15^2+10^2) = root 725 =26.925

so max integer length =26

Like? Yes (1) | No   

SUDESHNA SEN   14 years AGO

We need to find the diagonal from the lower corner to the upper corner (d) of the room by using the three-dimensional version of the Pythagorean Theorem.
The formula for that is x^2+y^2+z^2 = d^2.
So we have 20^2 + 15^2 + 10^2 = 400 + 225 + 100 = 725.
Therefore, the maximum length of the rod is= sq. root of 725= 26.93 feet.
So, the maximum length (in integer)of the rod is= 26 feet..... Option 9)

Like? Yes (1) | No   

ASHOK ROY   14 years AGO

We need to find the diagonal from the lower corner to the upper corner (d) of the room by using the three-dimensional version of the Pythagorean Theorem.
The formula for that is x^2+y^2+z^2 = d^2.
So we have 20^2 + 15^2 + 10^2 = 400 + 225 + 100 = 725.
Therefore, the maximum length of the rod is= sq. root of 725= 26.93 feet.
So, the maximum length (in integer)of the rod is= 26 feet..... Option 9)

Like? Yes (1) | No   

Mamon Sengupta   14 years AGO

We need to find the diagonal from the lower corner to the upper corner (d) of the room by using the three-dimensional version of the Pythagorean Theorem.
The formula for that is x^2+y^2+z^2 = d^2.
So we have 20^2 + 15^2 + 10^2 = 400 + 225 + 100 = 725.
Therefore, the maximum length of the rod is= sq. root of 725= 26.93 feet.
So, the maximum length (in integer)of the rod is= 26 feet..... Option 9)

Like? Yes (1) | No   

Trishita Dasgupta   14 years AGO

We need to find the diagonal from the lower corner to the upper corner (d) of the room by using the three-dimensional version of the Pythagorean Theorem.
The formula for that is x^2+y^2+z^2 = d^2.
So we have 20^2 + 15^2 + 10^2 = 400 + 225 + 100 = 725.
Therefore, the maximum length of the rod is= sq. root of 725= 26.93 feet.
So, the maximum length (in integer)of the rod is= 26 feet..... Option 9)

Like? Yes (1) | No   

sanjib biswas   14 years AGO

sqrt of (400+225+100)=26.92 but Maximum length (in integer)
of a rod placed in the room is 26

Like? Yes (1) | No