Robert purchased a machine for Rs. 80,000. After spending Rs.5000 on repair and Rs.1000 on transport

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17 Jun 2019 Profit & Loss

Robert purchased a machine for Rs. 80,000. After spending Rs.5000 on repair and Rs.1000 on transport he sold it with 125% profit. What price did he sell the machine?

OPtion

1) 107500
2) 108500
3) 109500
4) 106500
5) 193500
6) 104500
7) 194500
8) 198500
9) 195500
10) None of these

Solution

CP of Machine for John include all costs = 80000 + 5000 + 1000 = 86000
SP = 225 * 86000/100 = 193500

Correct Option: 5 Best Solution (10)

G.S.Kantharao   4 years AGO

C.P =₹80000
Repairs =₹5000
Transport=₹1000
Profit=125%
S.P=₹86000×225%=₹193500
My option is 5

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SAYAN CHATTERJEE   4 years AGO

Selling price = (80000+1000+5000)*(1+125/100)= 193500.
Option 5.

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A janani hariprasad   4 years AGO

sp=cp(100+p%)/100
overall cp is 86000
solving we get 193500

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RAMADURAI NATESAN   4 years AGO

Purchase price plus cost incurred = 86000.
Selling price = 2.25 * 86000 = 193500

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Elizabeth Pothen   4 years AGO

Cost price = 80,000+ 5000+6000= 86,000
Profit = 1.25
Profit = (SP - CP)/CP
2.25 CP = SP
2.25 * 86000 = 193500
So SP = 193500

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Karan   4 years AGO

selling price = (80000+5000+1000)*(100+125)/100= 193500

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S.SAI DATTA   4 years AGO

Total cost price 80000+5000+1000= 86000,
125% profit on 86000 is 193500

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monali dandpat   4 years AGO

c.p of machine=80,000
repairing=5,000
transport=1,000
taotal c.p=80,000+5,000+1000=86,000
and profit=125%
s.p=86,000*225/100=193500

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NAGMA   4 years AGO

CP= 80,000+5000+1000
PROFIT= 125

S.P= {(100+GAIN%)/100}* CP

=(100+125/100)* 86000

= (225/100)* 86,000

= 193500

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srivalli kanagala   4 years AGO

100=86000
125=125*86000/100
100+125=86000+107500

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