Considering base is 10, so 1 could be represented as Log10
=> log2 + log(3x+1) = log(2x-9) + log100
Let’s revise the formula for Logs
Log(XY) = LogX+LogY
Applying the formula we get:
Log[2*(3x+1)] = Log[100*(2x-9)]
Solving
=> 6x + 2 = 200x - 900
=> 194x= 902
=> x = 451/97