A fractional no. is such that its numerator is 2 less then denominator. If both numerator & denom

M4maths Previous Puzzles

25 Jun 2010 find the numerator?

A fractional no. is such that its numerator is 2 less then denominator. If both numerator & denominator increase by 1
the fraction becomes 4/5. What will be the numerator of the no.

OPtion

1) 1
2) 2
3) 3
4) 4
5) 5
6) 6
7) 7
8) 8
9) 9
10) 10

Solution

Let the number is x/x+2
(x+1)5 = (X+3)4
5x+5 = 4X+12
x=7

Correct Option: 7 Best Solution (17)

Trishita Dasgupta   14 years AGO

Let the no. be x/(x+2).
Then, as per given condition,
(x+1)/(x+2+1)=4/5
or, (x+1)/(x+3)=4/5
or,5x+5=4x+12
or, x=7 or the numerator of the no. is 7..... Option 7)

Like? Yes (2) | No   

Dr.Dipin Singh   14 years AGO

A fractional no. is such that its numerator is 2 less then denominator. If both numerator & denominator increase by 1
the fraction becomes 4/5.

Final fraction is 4/5.
Now numerator is 2 less then denominator in original fraction and final fraction.

so final fraction is 4/5 or 8/10 where numerator and denominator is increased by 1 from initial fraction.
Then initial fraction is 7/9.

Numerator is 7.

Like? Yes (2) | No (1)  

HARMEET KAUR   14 years AGO

2(4/5)=8/10 difference=10-8=2

subtracting 1 from 8
we get 7

Like? Yes (2) | No (1)  

Pargat Pal Singh   14 years AGO

If x is the required numerator, then the number is x/x+2, then
new number x+1/x+3= 4/5;then
5*(x+1)= 4*(x+3) or 5x-4x= 12-5=7.. option 7

Like? Yes (2) | No (1)  

kewal   14 years AGO

Fraction is 7/9.
If both numerator & denominator increase by 1
the fraction becomes 8/10 or 4/5

Like? Yes (2) | No (1)  

Dolly   14 years AGO

If x is numerator, then ..

(x+1)/(x+2+1)= 4/5 or x+1)/(x+3)= 4/5

mean x=7

Like? Yes (2) | No (1)  

Mayur   14 years AGO

taking numerator as x and denom as x+2 and putting x+1/x+3=4/5, we get, x=7

Like? Yes (2) | No (1)  

Karan   14 years AGO

if x is numerator of number, then fraction is x/x+2.

also as per given condition

x+1/x+3=4/5; then x=7

Like? Yes (2) | No (1)  

Prerna   14 years AGO

when num is 7, fraction is 7/9.

adding 1 in num and denom, we get 8/10 which is equal to 4/5.

Like? Yes (2) | No (1)  

Saswata Chakraborty   14 years AGO

the original fraction is 7/9
when increased by 1 to num and deno it becomes 8/10=4/5

Like? Yes (2) | No (1)  

Saravanan   14 years AGO

((x-2)+1)/(x+1)=4/5

then x=9

x-2=numerator
9-2=7.

Like? Yes (2) | No (1)  

SUDESHNA SEN   14 years AGO

Let the no. be x/(x+2).
Then, as per given condition,
(x+1)/(x+2+1)=4/5
or, (x+1)/(x+3)=4/5
or,5x+5=4x+12
or, x=7 or the numerator of the no. is 7..... Option 7)

Like? Yes (2) | No (1)  

Mamon Sengupta   14 years AGO

Let the no. be x/(x+2).
Then, as per given condition,
(x+1)/(x+2+1)=4/5
or, (x+1)/(x+3)=4/5
or,5x+5=4x+12
or, x=7 or the numerator of the no. is 7..... Option 7)

Like? Yes (2) | No (1)  

ASHOK ROY   14 years AGO

Let the no. be x/(x+2).
Then, as per given condition,
(x+1)/(x+2+1)=4/5
or, (x+1)/(x+3)=4/5
or,5x+5=4x+12
or, x=7 or the numerator of the no. is 7..... Option 7)

Like? Yes (1) | No   

Sudeshna Sengupta   14 years AGO

Let the no. be x/(x+2).
Then, as per given condition,
(x+1)/(x+2+1)=4/5
or, (x+1)/(x+3)=4/5
or,5x+5=4x+12
or, x=7 or the numerator of the no. is 7..... Option 7)

Like? Yes (1) | No   

Parbati Sen   14 years AGO

Let the no. be x/(x+2).
Then, as per given condition,
(x+1)/(x+2+1)=4/5
or, (x+1)/(x+3)=4/5
or,5x+5=4x+12
or, x=7 or the numerator of the no. is 7..... Option 7)

Like? Yes (1) | No   

Dimple   14 years AGO

numerator is 2 less then denominator.
so fraction is x/x+2.If both numerator & denominator increase by 1, fraction becomes
x+1/x+3 which is equal to 4/5.
solving it , we get x=7.

Like? Yes (1) | No (1)