What is the value of x^3 + y^3 + z^3 – 3xyz, when x = 2, z = –3 and y = 1 ?

M4maths Previous Puzzles

07 Jan 2020 Solve

What is the value of x^3 + y^3 + z^3 – 3xyz, when x = 2, z = –3 and y = 1 ?

OPtion

1) 1
2) 2
3) 6
4) -4
5) -6
6) 0
7) -1
8) 8
9) 4
10) None of these

Solution

x^3 + y^3 + z^3 – 3xyz = 2^3 + 1^3 + (-3)^3 - 3 *2*1*(-3)
=> 8 + 1 - 27 + 18 = 0

Correct Option: 6 Best Solution (2)