In a party there are 49 persons present. If each of them shakes hand with all the other persons,in t

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21 Aug 2020 Handshakes

In a party there are 49 persons present. If each of them shakes hand with all the other persons,in total how many handshakes will take place?

OPtion

1) 1116
2) 1126
3) 1136
4) 1146
5) 1156
6) 1166
7) 1170
8) 1176
9) 1196
10) None of these

Solution

Out of 49 persons, the first person will shake hand with 48 persons.
The second person will shake hand with 47 persons (because he has already shaken hand with first person).
The third person will shake hand with 46 persons and so on. The second last person shakes hand with only one person. And last will shake hand with none
(because he has already shaken hand with all persons).
In order to find the total number of handshakes you have to add all the natural numbers from 1 to 48 i.e. ∑ 48.
∑48 = 48 x 49/2 = = 1176 handshakes.

Correct Option: 8 Best Solution (5)

Dr. Divya   3 years AGO

Every person shook hand with 48 persons.
Each handshake is common between two persons.
Hence total handshakes = 49*48/2= 1176

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RAMADURAI NATESAN   3 years AGO

Ans .= 49 C 2 = 49 *48 /2 =1176

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SAYAN CHATTERJEE   3 years AGO

total handshakes = 49C2= 1176.
Option 8.

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Bhargav   3 years AGO

no.of hand-shakes= 49(49-1)/2
= 49*24=1176

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G.S.Kantharao   3 years AGO

Sigma 48/2=48*49/2=1176
My option is 8✍️

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