The price of a diamond is decreased from Rupees one crore to Rupees eighty five lakhs. Find the perc

M4maths Previous Puzzles

24 Aug 2020 Percentage

The price of a diamond is decreased from Rupees one crore to Rupees eighty five lakhs. Find the percentage of decrease.

OPtion

1) 14.29
2) 16.67
3) 25.00
4) 20.00
5) 12.50
6) 10.00
7) 15.00
8) 24.00
9) 19.00
10) None of these

Solution

10000000 - 8500000 = 1500000
% = 1500000*100/10000000 = 15%

Correct Option: 7 Best Solution (9)

G.S.Kantharao   4 years AGO

Price of diamond =1cr.
Decreased to=85L
% of Decrease=15L*100/100L=15%
My option is 7✍️

Like? Yes | No   

Varun   4 years AGO

Decrease % = (Initial - Later)/Initial
= (100-85)/100
= 15%
= Option (7)

Like? Yes | No   

M4 Murali   4 years AGO

(15L/100L)*100

Like? Yes | No   

RAMADURAI NATESAN   4 years AGO

Decrease = 15 lakhs. % = 15/100 = 15 %

Like? Yes | No   

SAYAN CHATTERJEE   4 years AGO

In 1 crore price, it has been decreased to 85 lakhs.
so, decrement is 15%.
Option 7.

Like? Yes | No   

Bhargav   4 years AGO

(15,00,000*100)/1,00,00,000
=15%

Like? Yes | No   

Adwaitha   4 years AGO

New prize =85 lakhs
Decrease in price=15 lakh
Decrease%=15lakh/1 crore *100=15%

Like? Yes | No   

Rahul Bathla   4 years AGO

Change in price=10000000-8500000=1500000
¬(1500000/10000000)*100
Equals 15

Like? Yes | No   

Pooja Sithrubi   4 years AGO

amt of decrease = 10000000- 8500000= 1500000
original amt= 10000000
%decrease= (amt of decrease)/(original amt) *100
= 15.00

Like? Yes | No