A man says to his son, "I am twice as old as you at present yet 20 years ago I was four times as old as you."
Sum of the ages of father and son after 1 year will be
Let at present age of father = x and that of son = x/2
20 years ago, the age of father = x-20 and that of son = x/2 – 20 According to the given condition x-20 = 4(x/2 -20
=> x-20 = 2x - 80
=> x = 60
Hence age of father = 60 and that of son = 30 at present
After 1 year sum of their ages = 61 + 31 = 92
In mathematics you don't understand things. You just get used to them.
Johann von Neumann
The difference between a two-digit number and the number obtained by interchanging the digits is 36. What is the difference between the sum and the difference of the digits of the number if the ratio between the digits of the number is 1 : 2 ?