A man says to his son, "I am twice as old as you at present yet 20 years ago I was four times as old as you."
Sum of the ages of father and son after 1 year will be
Let at present age of father = x and that of son = x/2
20 years ago, the age of father = x-20 and that of son = x/2 – 20 According to the given condition x-20 = 4(x/2 -20
=> x-20 = 2x - 80
=> x = 60
Hence age of father = 60 and that of son = 30 at present
After 1 year sum of their ages = 61 + 31 = 92