In JEECAT exam, a student scores four marks for every correct answer and loses one mark for every wr

M4maths Previous Puzzles

25 Aug 2020 Marks

In JEECAT exam, a student scores four marks for every correct answer and loses one mark for every wrong answer. If Jaggu attempts all sixty questions and secures 130 marks, the no of questions Jaggu attempted correctly is :

OPtion

1) 44
2) 25
3) 46
4) 39
5) 36
6) 38
7) 45
8) 40
9) 43
10) None of these

Solution

Let the number of correct answers be X.

Number of incorrect answers = (60 – X).

4x – (60 – x) = 130

=> 5x = 190

=> x = 38

Correct Option: 6 Best Solution (11)

Dr.Dipin Singh   3 years AGO

If Jaggu anaswered x questions correct, then
4x-(60-x)=130
5x=190
x=38

Like? Yes (3) | No   

veni   3 years AGO

assume correct answer is X, and wrong answer is Y. then X+Y=60Treated as equation 1 . and 4X-1Y=130treated as equation 2. then solving both we get X=38. correct questions answering.

Like? Yes (1) | No (1)  

Mukesh   3 years AGO

on every wrong answer, Student will loose 5 marks.
here he lost 110 marks,so 110/5=22 wrong answers and hence 38 are correct answers.

Like? Yes | No   

SAYAN CHATTERJEE   3 years AGO

let correct answers be x and wrong be y
so, x+y= 60
4x-y= 130
x= 38.
Option 6.

Like? Yes | No (1)  

G.S.Kantharao   3 years AGO

Let x are correct
4x-(60-x)*1=130
5x=190=>x=38
My option is 6 ✍️

Like? Yes (1) | No (2)  

Rahul Bathla   3 years AGO

X: correct ans.
Y: wrong ans.
X+y=60 _ 1
4x+(-1)y=130 _ 2
Add 1 and 2 equation
5x=190
X=38

Like? Yes | No (1)  

M4 Murali   3 years AGO

x correct,y-wrong
4x-y=130
x+y=60
from 2 eqns x=38

Like? Yes | No (1)  

Varun   3 years AGO

Given 4c-w=130
c+w=60
Solving, c = 38
= Option (6)

Like? Yes | No (1)  

RAMADURAI NATESAN   3 years AGO

C + W = 60 and 4 C - W = 130.
Solving, C = 38.

Like? Yes | No (1)  

Satakshi   3 years AGO

No. Of correct questions=x
Incorrect=60-x
A/q
4x-1*(60-x)=130
4x-60+x=130
5x=190
x=38

Like? Yes | No (1)  

PANKAJ KUMAR   3 years AGO

obvious

Like? Yes | No (1)