An alloy contains 51 % of bronze. What quantity of alloy is required to get 370 g of bronze?

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12 Nov 2020 PERCENTAGE

An alloy contains 51 % of bronze. What quantity of alloy is required to get 370 g of bronze?

OPtion

1) 725.490
2) 944.2
3) 950
4) 1000
5) 980.5
6) 750.21
7) 830
8) 840.63
9) 952.32
10) None of the above

Solution

Let the quantity of alloy required = x g
Then 51 % of x =370 g
51/100 × x = 370 g
x = (370 × 100)/51 g
x = 37000/51 g
x = 725.490 g

Correct Option: 1 Best Solution (3)

RAMADURAI NATESAN   3 years AGO

Given 0.51 A = 370 g.
A = 370/0.51 = 725.490

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Varun   3 years AGO

370*100/51

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HARMEET KAUR   3 years AGO

Required alloy = 100*370/51= 725.49 gms

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