We have a 15-litre solution containing 40% of DI water in the HCL.
=> Quantity of DI water in the solution =(15* 40)/100= 6
Now 5 litre of HCL is added to the solution.
=> Total quantity of the new solution = 15 + 5= 20
Percentage of DI water in the new solution = 6*100/20
= 600/20 = 30%