A father said to his son that he was thrice of his age 15 years before and will be twice of his age
10 years hence. Difference of the ages of father and son is
Let the age of father is f and that of son is s at present
According to the given conditions
f - 15 = 3 (s-15) => f – 3s = -30 (i)
f + 10 = 2 (s+10) => f – 2s = 10 (ii)
On solving (i) and (ii), we get f = 90; s = 40