Minimum sum of 5 positive integers on the basis of following conditions 1. 1 is not allowed 2. Two

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29 Jun 2021 Number

Minimum sum of 5 positive integers on the basis of following conditions
1. 1 is not allowed
2. Two successive integers are not allowed
3. First two prime numbers are not allowed

OPtion

1. 45
2. 41
3. 20
4. 37
5. 40
6. 22
7. 38
8. 43
9. 44
10. None of the above

Solution

1. 1 is not allowed
2. Two successive integers are not allowed
3. First two prime numbers (2,3) are not allowed .
Minimum possible number is 4.
Next number can be 6 only as two successive integers are not allowed.
Under given conditions, Minimum sum of 5 positive integers will be 40 as 4+6+8+10+12=40.

Correct Option: 5 Best Solution (5)

G.S.Kantharao   3 years AGO

The integers are 4,6,8,10,12
Sum =40
My option is 5 👈

Like? Yes (2) | No   

Billal Hossain   3 years AGO

conditions:
1) 1 is not allowed
2) first two prime numbers are not allowed. so 2, 3 are not allowed
3) successive integers are not allowed
Therefore, Minimum sum of 5 integers= 4+6+8+10+12
=40
So, My option is (5)

Like? Yes (1) | No   

SAYAN CHATTERJEE   3 years AGO

(4+6+8+10+12)= 40.
Option 5.

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Chinmay Swarup Chiranjeevi   3 years AGO

1 is not allowed
First two prime no are not allowed
So we start from 4
4 6 8 10 12
Total sum = 40

Like? Yes | No   

MRITUNJAY KUMAR   3 years AGO

First, the five positive integers are 4,6,8,10, and 12.
their sum =40

Like? Yes | No