3 nonzero positive integers x < y < z are such that their sum is 7. The sum of their squares is?

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24 Aug 2010 3 nonzeo numbers

3 nonzero positive integers x < y < z are such that their sum is 7. The sum of their squares is?

OPtion

1) 20
2) 27
3) 17
4) 37
5) 49
6) 19
7) 21
8) 15
9) 10
10) 30

Solution

Only possible set is 1, 2 and 4

Correct Option: 7 Best Solution (14)

~Sandeep~   13 years AGO

x=1, y=2, z=4,=> 1*1+2*2+4*4=21

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Dr.Dipin Singh   13 years AGO

Numbers are 1,2,4.

Sum of squares =1+4+16=21

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balaji   13 years AGO

(1+2+4)=7
(1^2)+(2^2)+(4^2)=21

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Karthik Pandiyan   13 years AGO

To satisfy the x

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JeyaMurugan   13 years AGO

here x

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Dinesh Babu   13 years AGO

the three nonzero numbers are 1 2 4. their sum is 7.
(1*1)+(2*2)+(4*4)=21.. Answer is 21

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Sukham   13 years AGO

1+4+16=21

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senthilkumaran   13 years AGO

Sum of the integer is = 7, So let assume the lowest positive integer which provide a sum as 7. That is, 1+2+4=7 ===> sum of their square is: 1+4+16=21. Obtained......

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HARMEET KAUR   13 years AGO

Sum of squares of 1,2,4 is 21.

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Mayur   13 years AGO

1^2+2^2+4^2=1+4+16=21

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MP    13 years AGO

1+2+4=7;
1+4+16=21

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Pritam Chatterjee   13 years AGO

Numbers are 1,2,4
So sum of there Squeres will be 1+4+16=21

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SUDESHNA SEN   13 years AGO

The only possible combination is x=1, y=2 and z=4.
So, the sum of their squares is= 1^2+2^2+4^2= 21..... Option 7)

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ASHOK ROY   13 years AGO

The only possible combination is x=1, y=2 and z=4.
So, the sum of their squares is= 1^2+2^2+4^2= 21..... Option 7)

Like? Yes (1) | No