10 men & 15 women complete half of the work in 12 days and 6 men & 15 women complete one third of the work in 10 days. How many days are required to complete the same full work by taking 10 men and 30 women?
OPtion
1) 12
2) 16
3) 18
4) 20
5) 21
6) 24
7) 27
8) 30
9) data are insufficient
10) none of these
Solution
Assume 1 man in 1 day do x work and 1 women in 1 day do y work.
So
10x + 15y = 1/24
6x + 15y = 1/30
solving we get
x = 1/480
y = 1/720
so 10 men & 30 women in 1 day do 10/48 + 30/720 = 1/16 of work.
Whole work in 16 days.
mathematics is the art of managing numbers with mindful manner.
rekha gupta
The difference between a two-digit number and the number obtained by interchanging the digits is 36. What is the difference between the sum and the difference of the digits of the number if the ratio between the digits of the number is 1 : 2 ?