The speed of the train is two more than twice of the time taken to cover 1012 km at uniform speed. What is the ratio of the values of time taken to cover the distance and speed of the train?
Let time taken to cover distance=t, then Speed=(2+2t)
Distance = Speed x Time
1012 = (2+2t) x t
t² + t - 506 = 0
(t+23) (t-22) = 0
t= -23 or 22
Considering +ve value of time t=22
.'. Speed=(2+2x22)=46
Hence required ratio of time and speed = 22/46 = 11/23
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