In how many ways 9800 can be written as a product of two numbers ?

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14 Mar 2022 Number System

In how many ways 9800 can be written as a product of two numbers ?

OPtion

1) 24
2) 16
3) 12
4) 18
5) 14
6) 36
7) 32
8) 26
9) 20
10) None of these

Solution

9800 = 2^3 x 5^2 x 7^2
If a number is represented as p^a x q^b x r^c
Then, number of factors = (a+1)(b+1)(c+1)
.'. Number of factors = (3+1)(2+1)(2+1) = 36
And product of two factors = 36/2 = 18
Hence in 18 ways 9800 can be written as a product of two numbers.

Correct Option: 4 Best Solution (1)

G.S.Kantharao   2 years AGO

9800=2^3*5^2*7^2
No.of factors are (3+1)*(2+1)*(2+1)=36
No. of ways as a product of two numbers =36/2=18
My option is =4👈

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