A bag contains 5 green, 7 red and 4 white balls. If three balls are drawn one after the other with r

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01 Aug 2022 Probability

A bag contains 5 green, 7 red and 4 white balls. If three balls are drawn one after the other with replacement, then the probability of getting balls of same colour is:

OPtion

1) 1/4
2) 1/35
3) 1/64
4) 1/32
5) 7/80
6) 2/35
7) 4/35
8) 133/512
9) 133/1024
10) None of these

Solution

Total number of balls in a bag = 5+7+4 = 16
As the balls are drawn with replacement, so probability of drawing same colour ball each time will be same.
P(Drawing 3 Green balls) = (5/16)*(5/16)*(5/16) = 125/4096
P(Drawing 3 Red balls) = (7/16)*(7/16)*(7/16) = 343/4096
P(Drawing 3 White balls) = (4/16)*(4/16)*(4/16) = 64/4096
.'. Probability of getting balls of same colour = P(3 Green) + P(3 Red) + P(3 White) = 125/4096 + 343/4096 + 64/4096 = 532/4096 = 133/1024
Correct Option 9)

Correct Option: 9 Best Solution (2)

Pargat Pal Singh   2 years AGO

(5/16)^3 + (7/16)^3 +(4/16)^3 =133/1024

Like? Yes (3) | No   

RAMADURAI NATESAN   2 years AGO

Ans = (5^3 +7^3 + 4^3 ) / 16^3 =133 / 1024

Like? Yes | No