Nine men can finish a work in 20 days whereas 12 women can finish the same work in 18 days. If six m

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30 Jun 2022 Time and Work

Nine men can finish a work in 20 days whereas 12 women can finish the same work in 18 days. If six men and nine women started working together. After 8 days 3 women left and 2 new men joined the work, The group continued working together till the end of the work. In how many days will they be able to do the remaining work ?

OPtion

1) 45/8
2) 72/19
3) 75/17
4) 45/11
5) 72/13
6) 84/19
7) 65/17
8) 176/13
9) 108/13
10) None of these

Solution

9 men can finish work in 20 days, so 1 man's 1 day work=1/(9x20)=1/180
12 women can finish work in 18 days, so 1 woman's 1 day work=1/(12x18)=1/216
6 men & 9 women's 8 days work=8x(6/180 + 9/216)=3/5
Remaining work=1 - 3/5=2/5
Given, after 8 days 3 women left and 2 new men joined, so in new group there are 8 men and 6 women
Now 8 men + 6 women's 1 day work=8*(1/180) + 6*(1/216) = 13/180
.'. Time required to complete remaining work = (2/5)/(13/180) = 72/13 days
Correct Option 5)

Correct Option: 5 Best Solution (2)

G.S.Kantharao   1 year AGO

9 men can do in 20d
1 man can do in 1 d =1/180
12 women can do in 18d
1 woman can do in 1 day =1/216
6 men and 9 women can do in 1 day =6*1/180+9*1/216
=1/30+1/24 = 9/120=3/40
In 8 days =3*8/40=3/5
Remaining=2/5
8 men +6 women =8/180+6/216=2/45+1/36
=(8+5)/180=13/180
No of days to be taken for 2/5 work
(2/5)/(13/180)=2*180/5*13
=72/13
So my option is 5👈

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RAMADURAI NATESAN   1 year AGO

1M.Full work =180d. 1W= 216d.
6M + 9W ; 8d = 3/5W.Bal. = 2/5W.
8M+6W ; 1d = 13/180ofW.
2/5W 0rk= 2/5 *180/13 = 72/13

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