A two-digit number is chosen such that it is 18 more when digits are reversed. What is the probabili

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09 Aug 2022 Probability

A two-digit number is chosen such that it is 18 more when digits are reversed. What is the probability that sum of digits of this number is more than 10 ?

OPtion

1) 4/7
2) 1/2
3) 1/3
4) 3/7
5) 1/4
6) 3/8
7) 2/3
8) 2/7
9) 3/10
10) None of these

Solution

If x and y are digits of a number, then two-digit number=10x+y
Difference between original number & number formed by digits revered= (10y+x) - (10x+y) =18
⇒ y - x = 2
Values of y,x satisfying above condition for a two-digit numbers are (3,1) (4,2) (5,3) (6,4) (7,5) (8,6) (9,7)
Thus there are total 7 numbers 13, 24, 35, 46, 57, 68, 79
Numbers with sum of digits more than 10 are 57, 68, 79 , Total 3
Hence, required probability = 3/7
Correct Option 4)

Correct Option: 4 Best Solution (0)